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Talja [164]
3 years ago
11

A fair number cube with

Mathematics
1 answer:
malfutka [58]3 years ago
6 0

Answer:

b=15 percentage

a=20 percentage

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46÷6=? R ? What is the remainder for 46÷6= All i'm asking for is just the remainder.
Rom4ik [11]

Answer:

7.66666666667

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which of the following in an identity?
sammy [17]
By "which is an identity" they just mean "which trigonometric equation is true?"

What you have to do is take one of these and sort it out to an identity you know is true, or...

*FYI: You can always test identites like this:
Use the short angle of a 3-4-5 triangle, which would have these trig ratios:
sinx = 3/5    cscx = 5/3
cosx = 4/5   secx = 5/4
tanx = 4/3    cotx = 3/4
Then just plug them in and see if it works. If it doesn't, it can't be an identity!

Let's start with c, just because it seems obvious.
The Pythagorean identity states that sin²x + cos²x = 1, so this same statement with a minus is obviously not true.

Next would be d. csc²x + cot²x = 1 is not true because of a similar Pythagorean identity 1 + cot²x = csc²x. (if you need help remembering these identites, do yourslef a favor and search up the Magic Hexagon.)

Next is b. Here we have (cscx + cotx)² = 1. Let's take the square root of each side...cscx + cotx = 1. Now you should be able to see why this can't work as a Pythagorean Identity. There's always that test we can do for verification...5/3 + 3/4 ≠ 1, nor is (5/3 +  3/4)².

By process of elimination, a must be true. You can test w/ our example ratios:
sin²xsec²x+1 = tan²xcsc²x
(3/5)²(5/4)²+1 = (4/5)²(5/3)²
(9/25)(25/16)+1 = (16/25)(25/9)
(225/400)+1 = (400/225)
(9/16)+1 = (16/9)
(81/144)+1 = (256/144)
(81/144)+(144/144) = (256/144)
(256/144) = (256/144)
5 0
3 years ago
PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE HELP ME!!!!!!!! I HAVE 2 QUESTIONS THATS ALL. I WILL GIVE POINTS, FAN, MEDAL. PLEASE I
Soloha48 [4]
F(n)=4n+1 seems to be the basic function for these sets.
7 0
3 years ago
Read 2 more answers
A data set lists earthquake depths. The summary statistics are nequals300​, x overbarequals5.89 ​km, sequals4.44 km. Use a 0.01
kirza4 [7]

Answer:

Null hypothesis H_0:\mu=5.00km

Alternative hypothesis H_1:\mu\neq 5.00km

The p value is 0.000517, which is less than the significance level 0.01, therefore we reject the null hypothesis and conclude that population mean is not equal to 5.00.

Step-by-step explanation:

It is given that a data set lists earthquake depths. The summary statistics are

n=300

\overline{x}=5.89km

s=4.44km

Level of significance = 0.01

We need to test the claim of a seismologist that these earthquakes are from a population with a mean equal to 5.00.

Null hypothesis H_0:\mu=5.00km

Alternative hypothesis H_1:\mu\neq 5.00km

The formula for z-value is

z=\frac{\overline{x}-\mu}{\frac{s}{\sqrt{n}}}

z=\frac{5.89-5.00}{\frac{4.44}{\sqrt{300}}}

z=\frac{0.89}{0.25634351952}

z=3.4719

The p-value for z=3.4719 is 0.000517.

Since the p value is 0.000517, which is less than the significance level 0.01, therefore we reject the null hypothesis and conclude that population mean is not equal to 5.00.

6 0
3 years ago
What do the following two equations represent?
miv72 [106K]

Answer:

Intersecting but not perpendicular

Step-by-step explanation:

Assuming you forgot to add the = between y+5 and 2(1)

Since there is a opposite single variable in either equation the lines will intersect but not be perpendicular

3 0
2 years ago
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