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V125BC [204]
3 years ago
8

How do u write 2.45 in words

Mathematics
2 answers:
Genrish500 [490]3 years ago
8 0
It would likely just be written as "two point four five", or "two and forty-five hundredths".
Solnce55 [7]3 years ago
7 0
Hey there

The answer is two and forty-five hundredths

Hope this helps 

~ Jordan ~
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50 miles per hour as they have been driving at a constant speed of 50 miles per hour throughout the trip.300/6=50 and 250/5=50
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3 years ago
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The population of a town in 2007 is 113, 505
ELEN [110]

from 2007 to 2012 is only 5 years, so we can see this as a compound interest with a rate of 1.2% per annum for 5 years, so

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$113505\\ r=rate\to 1.2\%\to \frac{1.2}{100}\dotfill &0.012\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{per year, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=113505\left(1+\frac{0.012}{1}\right)^{1\cdot 5}\implies A=113505(1.012)^5\implies A\approx 120481

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2 years ago
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The answer is 176 because 86+86=176
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3 years ago
The altitude of an equilateral triangle is 5 cm. what is the length of a side of the triangle?
Grace [21]

Answer:

The length side of the triangle is \frac{10\sqrt{3}}{3}\ cm

Step-by-step explanation:

we know that

The equilateral triangle has three equal sides and three equal internal angles of measure of 60 degrees each.

Let

b------> the length side of the equilateral triangle

Applying Pythagoras theorem

b^{2}=(b/2)^{2}+5^{2}\\\\ b^{2}-(b/2)^{2}=25\\\\ (3/4)b^{2}=25\\ \\b^{2} =25*4/3\\ \\b=\frac{10}{\sqrt{3}}\ cm\\ \\b=\frac{10\sqrt{3}}{3}\ cm

3 0
4 years ago
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Answer:

9) Domain: 0≤x≤6

Range: -3≤y≤3

10) Domain: -∞≤x≤∞

Range: -∞≤y≤∞

11) Domain: -∞≤x≤∞

Range: y≥-2

13) Domain: -∞≤x≤∞

Range: -2≤y≤4

Step-by-step explanation:

9) Domain: 0≤x≤6

Range: -3≤y≤3

10) Domain: -∞<x<∞

Range: -∞<y<∞

11) Domain: -∞<x<∞

Range: y≥-2

13) I think you need to look at this one again.  It looks like:

Domain: -∞<x<∞

Range: -2≤y≤4

4 0
4 years ago
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