Since difference is subtraction, that means that y-2=9 and by adding 2 to both sides we get y=11
By simplifying ![\[x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x\]](https://tex.z-dn.net/?f=%5C%5Bx%20-%20%5Cfrac%7B%7B23%7D%7D%7B%7B%7Bx%5E2%7D%7D%7D%20-%20x%20-%2020%20-%20%5Cfrac%7B2%7D%7B5%7D%20-%20x%5C%5D)
. This will result in a simplified version of ![\[ - \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}\]](https://tex.z-dn.net/?f=%5C%5B%20-%20%5Cfrac%7B%7B5%7Bx%5E3%7D%20%2B%20102%7Bx%5E2%7D%20%2B%20115%7D%7D%7B%7B5%7Bx%5E2%7D%7D%7D%5C%5D)
.
The Simplifying Algorithm is a wonderful way to simplify complex mathematics problems. It can be used to solve equations, convert fractions to decimals, and perform many other math operations. In this problem, the Simplifying Algorithm will help you reduce
Since two opposites add up to 0, remove them from the expression.
![\[ - \frac{{23}}{{{x^2}}} - \frac{{102}}{5} - x\]](https://tex.z-dn.net/?f=%5C%5B%20-%20%5Cfrac%7B%7B23%7D%7D%7B%7B%7Bx%5E2%7D%7D%7D%20-%20%5Cfrac%7B%7B102%7D%7D%7B5%7D%20-%20x%5C%5D)
Write all numerators above the least common denominator 5x2
![\[ - \frac{{115 + 102{x^2} + 5{x^3}}}{{5{x^2}}}\]](https://tex.z-dn.net/?f=%5C%5B%20-%20%5Cfrac%7B%7B115%20%2B%20102%7Bx%5E2%7D%20%2B%205%7Bx%5E3%7D%7D%7D%7B%7B5%7Bx%5E2%7D%7D%7D%5C%5D)
Use the commutative property to reorder the terms so that constants on the left
![\[\frac{{ - 5{x^3} - 115 - 102{x^2}}}{{5{x^2}}}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B%7B%20-%205%7Bx%5E3%7D%20-%20115%20-%20102%7Bx%5E2%7D%7D%7D%7B%7B5%7Bx%5E2%7D%7D%7D%5C%5D)
Rearrange the terms
![\[\frac{{ - 5{x^3} - 102{x^2} - 115}}{{5{x^2}}}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B%7B%20-%205%7Bx%5E3%7D%20-%20102%7Bx%5E2%7D%20-%20115%7D%7D%7B%7B5%7Bx%5E2%7D%7D%7D%5C%5D)
By reording the terms
Hence, by simplifying this equation, divide both numerator and denominator. This will result in a simplified version of .
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X=-2 is shown on the graph.
Answer:
<u>Secant</u>: a straight line that intersects a circle at two points.
<u>Intersecting Secants Theorem</u>
If two secant segments are drawn to the circle from one exterior point, the product of the measures of one secant segment and its external part is equal to the product of the measures of the other secant segment and its external part.
From inspection of the given diagram:
- M = Exterior point
- MK = secant segment and ML is its external part
- MS = secant segment and MN is its external part
Therefore:
⇒ ML · MK = MN · MS
Given:
- MK = (x + 15) + 6 = x + 21
- ML = 6
- MS = 7 + 11 = 18
- MN = 7
Substituting the given values into the formula and solving for x:
⇒ ML · MK = MN · MS
⇒ 6(x + 21) = 7 · 18
⇒ 6x + 126 = 126
⇒ 6x = 0
⇒ x = 0
Substituting the found value of x into the expression for KL:
⇒ KL = x + 15
⇒ KL = 0 + 15
⇒ KL = 15
Answer:12 cups of sugar
Step-by-step explanation:
There is 6 batches each batch has two cups you would do 6x2 for 12 cups.
