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4 years ago

Solve for x in the equation 3 x squared minus 18 x + 5 = 47.

Mathematics

1 answer:

svetlana [45]4 years ago

4 0

Answer:

(4+√142)/(3) or x=(4-√142) /3

Step-by-step explanation:

(4+√142)/(3) or x=4-√142 /3

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The Russell family and the Gonzalez family each used their sprinklers last summer. The water output rate for the Russell family'

Alexus [3.1K]

Answer:

Russell family's sprinkler: 40 hours

Gonzales family's sprinkler: 20 hours

Step-by-step explanation:

Let's call the amount of time the Russell family's sprinkler was on by X, and the Gonzales family's sprinkler by Y.

We can then formulate the equations:

X + Y = 60

X*35 + Y*40 = 2200

We can solve this system multiplying the first equation by 35, and then subtracting the result from the second equation:

35*X + 35*Y = 2100

5*Y = 100

Y = 20

from the first equation:

X + 20 = 60

X = 40

Russell family's sprinkler: 40 hours

Gonzales family's sprinkler: 20 hours

8 0

3 years ago

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swat32

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Step-by-step explanation:

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3 years ago

Hector works 12 hours per week at a part-time

rewona [7]

Answer:

Step-by-step explanation:

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3 years ago

24 water bottles for $2.95

N76 [4]

Answer:

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Step-by-step explanation:

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3 years ago

Lotteries are an important income source for various governments around the world. However, the availability of lotteries and ot

SashulF [63]

Answer: 0.0473

Step-by-step explanation:

Given : The proportion of gambling addicts : p=0.30

Let x be the binomial variable that represents the number of persons are gambling addicts.

with parameter p=0.30 , n= 10

Using Binomial formula ,

$P(x)=^nC_xp^x(1-p)^{n-x}$

The required probability = $P(x>5)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\=^{10}C_6(0.3)^6(0.7)^{4}+^{10}C_7(0.3)^7(0.7)^{3}+^{10}C_8(0.3)^8(0.7)^{2}+^{10}C_9(0.3)^9(0.7)^{1}+^{10}C_{10}(0.3)^{10}(0.7)^{0}\\\\=\dfrac{10!}{4!6!}(0.3)^6(0.7)^{4}+\dfrac{10!}{3!7!}(0.3)^7(0.7)^{3}+\dfrac{10!}{2!8!}(0.3)^8(0.7)^{2}+\dfrac{10!}{9!1!}(0.3)^9(0.7)^{1}+(1)(0.3)^{10}\\\\=0.0473489874\approx0.0473$

Hence, the required probability = 0.0473

5 0

3 years ago