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3 years ago

4^n=16 Can someone please help me answer this question ?

Mathematics

1 answer:

Firdavs [7]3 years ago

4 0

$4^n=16\\\\4^n=4^2\Rightarrow n=2\\\\Answer:\ n=2\\\\\text{Check:}\\\\L=4^2=16\\R=16\\L=R\qquad CORRECT!!\ :)$

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A number has 2 tens and 15 ones. Write the number in words.

Crank

Two tens fifteen ones

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3 years ago

If the correlation coefficient in an ordinary least squares regression = 1.00, then A. all the data points must fall exactly on

Hatshy [7]

Answer: Option A is correct.

Step-by-step explanation:

The correlation coefficient(r) is a statistical measure that computes the strength of the relationship between two variables.

It lies between -1 and 1.

If the correlation coefficient in an ordinary least squares regression = 1.00.

That indicates that there is a perfect relationship between the variables.

i.e. all the data points must fall exactly on a straight line with a positive slope. .

[when r is positive, the slope of the line is positive].

i.e. option A is correct.

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3 years ago

Which statement about 2(×+4) is true ?

ahrayia [7]

2x + 8 would be the simplified version of this question

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3 years ago

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If there are 32 boys and 56 girls in a room, fill out all of the possible ratios of boys to girls that could be made.

leonid [27]

Answer:

4/7

Step-by-step explanation:

32/56=4/7

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3 years ago

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Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i

vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable X be defined as the number of students at a particular college who are smokers

The random variable X follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

$np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10$

Thus, a Normal approximation to binomial can be applied.

So,

$X\sim N(\mu=600, \sigma=\sqrt{120})$

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

= P (X > 280.50)

$=P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z$

*Use a z-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0

3 years ago