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Lynna [10]
3 years ago
7

Original amount: 27 End amount: 38.61 Increase or decrease

Mathematics
1 answer:
vichka [17]3 years ago
5 0

Answer:

increase

Step-by-step explanation:

11.61 was added to 27

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What is the GCF of 28a^3 b and 16ab ? <br><br> A)4ab<br> B)4a3b<br> C)28ab<br> D)112a3b2
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28a⁴b: 2 · 2 · 7 · a · a · a · a · b
 16ab: 2 · 2 · 2 · 2 · a · b

GCF(28a⁴b, 16ab) = 4ab

The answer is A.
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3 years ago
Write the related facts for the set of numbers.<br> 3,7,21
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They all have either a common factor, common multiple, LCF, GCF, LCM, or GCM. The G and L stand for greater and least.
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3 years ago
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Given y = x + 1 Calculate y if x = 3. y is a natural number​
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Answer:

y = 4

Step-by-step explanation:

If 3 is x than you can substitute x for 3. y = 3 + 1. Then when you add  y = 4

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3 years ago
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Paul Havlik promised his grandson Jamie that he would give him $7,100 7 years from today for graduating from high school. Assume
Dominik [7]

Answer:

\large \boxed{\$4100.07}

Step-by-step explanation:

The formula for the future value (FV) of an investment earning compound interest is

FV = PV \left (1 + \frac{r}{n} \right )^{nt}

where

PV = the present value (PV) of the money invested

  r = the annual interest rate expressed as a decimal fraction

  t = the time in years

 n = the number of compounding periods per year

Data:

FV = $7100

  r =  8 % = 0.08

  t = 7 yr

 n = 2

Calculation:

\begin{array}{rcl}\\7100& =& PV \left (1 + \dfrac{0.08}{2} \right )^{2 \times 7}\\\\& =& PV (1 + 0.04)^{14}\\\\& =&PV (1.04)^{14}\\& =& PV(1.731676)\\PV& =& \dfrac{7100}{1.731676}\\\\& =& \mathbf{4100.07}\\\end{array}\\\text{The present value of the money is $\large \boxed{\mathbf{\$4100.07}}$}

4 0
3 years ago
It is claimed that an automobile is driven on the average more than 20,000 kilometers per year. To this claim, a random sample o
Aleonysh [2.5K]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Sample mean(x) = 23500

Sample standard deviation (sd) = 3900

Sample size (n) = 20

Population mean (m) = 20,000

Null hypothesis : m = 20000

H1: m > 20000

To obtain the z-score :

(population mean - sample mean) / (sample standard deviation /√sample size)

(x - m) / (sd/√n)

(23500 - 20000) / (3900 / √20)

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3500 / 872.06651

= 4.0134

Get the P value to know if to reject or accept the null:

P(z > 4.0134) = 1 - P(z < 4.0134)

P(z < 4.0134) = 1

1 - P(z < 4.0134) = 1 - 1 =0

Since P value is < alpha, we reject the null.

Hence average is > 20000

3 0
3 years ago
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