Question

Which explains how to show that x= -8/3 is a root of 9x^2+48x+64= 0 ?

Answer 1

Step-by-step explanation:

$9 {( - \frac{8}{3}) }^{} {}^{2} + 48( - \frac{8}{3} ) + 64 \\ \\ 9( - \frac{64}{9} ) - \frac{48}{3} + 64 \\ \\ - 64 - 16 + 64 = - 16$