3x6-10. The ten is supposed to be abive the six.
No it is not, the solution would need to be (2,-4) in order to satisfy the equation y = -2x -- like so -4 = -2(2)
-4 = -4, otherwise the equation won't be satisfied.
Let that be

Two vertical asymptotes at -1 and 0

If we simply

- Denominator has degree 2
- Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
- But there should be a x intercept at -3 so one zeros should be -3
Find a equation
Find zeros
Horizontal asymptote
So our equation is

Graph attached
Answer:
JM = 10
Step-by-step explanation:
Because MN║JL,

= 
2(5) = 1(2x + 4)
10 = 2x + 4
2x = 6
x = 3
JM = 2x + 4 = 2(3) + 4 = 6 + 4 = 10