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3 years ago

Please answer this correctly

Mathematics

1 answer:

nikklg [1K]3 years ago

8 0

Answer:

20-29: Make it 1 unit tall

30-39: Make it 5 units tall

Step-by-step explanation:

20-29: 22 (1 number)

30-39: 31, 32, 32, 32, 32 (5 numbers)

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Solve the equation <br>y=2x-4, 3x+y=11

Ostrovityanka [42]

Answer:

(3, 2)

Step-by-step explanation:

Given the 2 equations

y = 2x - 4 → (1)

3x + y = 11 → (2)

Substitute y = 2x - 4 into (2)

3x + 2x - 4 = 11

5x - 4 = 11 ( add 4 to both sides )

5x = 15 ( divide both sides by 5 )

x = 3

Substitute x = 3 into (1) for corresponding value of y

y = (2 × 3) - 4 = 6 - 4 = 2

Solution is (3, 2)

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2 years ago

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A brother and a sister are in the same math class. there are 8 boys and 10 girls in the class. one boy and one girl are randomly

timama [110]

The best one is 1/9 maybe

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2 years ago

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P(x)=2x 4 −x 3 +2x 2 −6P, left parenthesis, x, right parenthesis, equals, 2, x, start superscript, 4, end superscript, minus, x,

Tresset [83]

Answer:

P = -x^3 +12 / x+6

Step-by-step explanation:

Let's solve for p.

px=(2)(4)−x3+(2)(2)−6p

Step 1: Add 6p to both sides.

px+6p=−x3−6p+12+6p

px+6p=−x3+12

Step 2: Factor out variable p.

p(x+6)=−x3+12

Step 3: Divide both sides by x+6.p(x+6)

x+6

−x3+12

x+6

−x3+12

x+6

5 0

2 years ago

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow

Mrrafil [7]

Answer:

$\displaystyle \frac{54}{5405}$ .

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

$\displaystyle \left(50\atop 5\right) = 2,118,760$ .

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

$\displaystyle \left( 28\atop 2\right) = 378$ .

Number of ways to choose 3 green candies out of a batch of 8:

$\displaystyle \left(8\atop 3\right)=56$ .

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

$\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168$ .