Evaluate 32 + (4c − 6c) + (2 + 6c) for c = 5. A.22 B.64 C.−10 D.54
2 answers:
Answer:
D. 54
Step-by-step explanation:
32 + (4c - 6c) + (2 + 6c)
Put c as 5 and evaluate.
32 + 4(5) - 6(5) + 2 + 6(5)
Multiply the terms.
32 + 20 - 30 + 2 + 30
Add or subtract the terms.
32 - 10 + 2 + 30
22 + 32
= 54
Answer:
The answer is option D
32 + (4c − 6c) + (2 + 6c)
c = 5
32 + ( 4(5) - 6(5)) + (2 + 6 (5)
= 32 + (20 - 30) + ( 2 + 30)
= 32 - 10 + 32
= 54
Hope this helps
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