Evaluate 32 + (4c − 6c) + (2 + 6c) for c = 5. A.22 B.64 C.−10 D.54

Mathematics

2 answers:

Butoxors [25]3 years ago

7 0

Answer:

D. 54

Step-by-step explanation:

32 + (4c - 6c) + (2 + 6c)

Put c as 5 and evaluate.

32 + 4(5) - 6(5) + 2 + 6(5)

Multiply the terms.

32 + 20 - 30 + 2 + 30

Add or subtract the terms.

32 - 10 + 2 + 30

22 + 32

= 54

sweet-ann [11.9K]3 years ago

5 0

Answer:

The answer is option D

32 + (4c − 6c) + (2 + 6c)

c = 5

32 + ( 4(5) - 6(5)) + (2 + 6 (5)

= 32 + (20 - 30) + ( 2 + 30)

= 32 - 10 + 32

= 54

Hope this helps

You might be interested in

John and Jim painted a

Harman [31]

1/4+5/12=3/12+5/12=8/12=4/6=2/3

they painted 2/3 of the fence

4 0

3 years ago

Which of the following is a polynomial with rootsnegative square root of 5, square root of 5, and 3

Scrat [10]

Answer:

P(x) = x³ - 3x² - 5x + 15

Step-by-step explanation:

∵ The roots of the polynomial are -√5 , √5 , 3

∴ The polynomial has 3 factors:

(x - √5) , (x + √5) , (x - 3)

∴ P(x) = (x - √5)(x + √5)(x - 3)

= (x² + √5x - √5x - 5)(x - 3)

= (x² - 5)(x - 3) = x³ - 3x² - 5x + 15

∴ P(x) = x³ - 3x² - 5x + 15

3 0

2 years ago

A bag holds 1 blue block and 3 yellow blocks. How many green blocks should be added to the bag to make the probability of random

Drupady [299]

$n$ - the number of green blocks which is equal to the number of favourable events
$1+3+n=4n$ - the number of all blocks, which is equal to the number of all possible outcomes

$P(A)=\dfrac{n}{4+n}=\dfrac{1}{2}\\
1\cdot( 4+n)=2\cdot n\\
4+n=2n\\
2n-n=4\\
n=4
$