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Goryan [66]
3 years ago
12

Kaylie had $1250 in her savings account. She withdrew $82 each month for 8 months in order to pay for a summer vacation. How muc

h did Kaylie have in her account at the end of the 8 months?
Mathematics
2 answers:
tester [92]3 years ago
8 0
I don't have any paper or a calculator nearby so ill tell you how to do it. the easiest way is to multiply 82 by 8 and subtract that from 1250
Vikentia [17]3 years ago
4 0
She would have 594 dollars left.
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Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou
Aleksandr [31]

Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

x=z+136

We also know that Y weighs 117 pounds more than car Z, this can be express as:

y=z+117

Finally, we know that the total weight of all the cars is 9439, then we have:

x+y+z=9439

Hence, we have the system of the equations:

\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}

Now that we have the value of z we plug it in the first two equations to find x and y:

\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}

Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

4 0
1 year ago
What is the maximum number of possible solutions for the system shown below?
vekshin1

Answer:

B:  4 solutions

Step-by-step explanation:

Combining the two equations results in 2x² = 52, or x² = 26.

This equation has two solutions:  x = ±√26.

As before, x² = 26.  If we substitute 26 for x² in the 1st equation, we get:

26 - 4y² = 16, or 4y² = 10, or y = ±√5/2.  Again:  two solutions.

If we take x to be +√26, y could be ±√(5/2).

Check:  is ( √26, √(5/2) ) a solution of the system?

Subbing these values into the first equation, we get:

26 - 4(5/2) = 16.  Is this true?

Then 10 = 10.  Yes.

Through three more checks, we find that this system has FOUR solutions.

5 0
3 years ago
A player of the National Basketball Association’s Portland Trail Blazers is the best free-throw shooter on the team, making 94%
g100num [7]

Answer:

The data for the probabilities are shown in the table below.

- A represents the probability of making the two shots for each of the best and worst shooter on the Portland Trail Blazers' team

- B represents the probability of making at least one shot for each of the best and worst shooter on the Portland Trail Blazers' team.

- C represents the probability of not making any of the two shots for each of the best and worst shooter on the Portland Trail Blazers' team.

N | Best ||| Worst

A | 0.8836 | 0.3136

B | 0.9964 | 0.8064

C | 0.0036 | 0.1936

It becomes evident why fouling the worst shooter on the team is a better tactic. The probabilities of the best shooter making the basket over the range of those two free shots are way better than the chances for the worst shooter.

Step-by-step explanation:

Part 1

Probability of the best shooter of the National Basketball Association’s Portland Trail Blazers making a shot = P(B) = 94% = 0.94

Probability that he doesn't make a shot = P(B') = 1 - 0.94 = 0.06

a) Probability that the best shooter on the team makes the two shots awarded = P(B) × P(B) = 0.94 × 0.94 = 0.8836

b) Probability that the best shooter on the team makes at least one shot.

This is a sum of probabilities that he makes only one shot and that he makes two shots.

Probability that he makes only one shot

= P(B) × P(B') + P(B') + P(B)

= (0.94 × 0.06) + (0.06 × 0.94) = 0.1128

Probability that he makes two shots = 0.8836 (already calculated in part a)

Probability that he makes at least one shot = 0.1128 + 0.8836 = 0.9964

c) Probability that the best shooter on the team makes none of the two shots = P(B') × P(B') = 0.06 × 0.06 = 0.0036

d) If the worst shooter on the team, whose success rate is 56% is now fouled to take the two shots.

Probability of the worst shooter on the team making a shot = P(W) = 56% = 0.56

Probability that the worst shooter on the team misses a shot = P(W') = 1 - 0.56 = 0.44

Part 2

a) Probability that the worst shooter on the team makes the two shots = P(W) × P(W)

= 0.56 × 0.56 = 0.3136

b) Probability that the worst shooter on the team makes at least one shot.

This is a sum of probabilities that he makes only one shot and that he makes two shots.

Probability that he makes only one shot

= P(W) × P(W') + P(W') + P(W)

= (0.56 × 0.44) + (0.44 × 0.56) = 0.4928

Probability that he makes two shots = 0.3136 (already calculated in part a)

Probability that he makes at least one shot = 0.4928 + 0.3136 = 0.8064

c) Probability that the worst shooter makes none of the two shots = P(W') × P(W') = 0.06 × 0.06 = 0.1936

From the probabilities obtained

N | Best ||| Worst

A | 0.8836 | 0.3136

B | 0.9964 | 0.8064

C | 0.0036 | 0.1936

It becomes evident why fouling the worst shooter on the team is a better tactic. The probabilities of the best shooter making the basket over the range of those two free shots are way better than the chances for the worst shooter.

Hope this Helps!!!

8 0
3 years ago
Read 2 more answers
Katie walked a total of 68 kilometers by making 34 trips to school. How many trips will Katie have to make in all to walk a tota
ZanzabumX [31]

Find the distance of each trip:

68 km / 34 trips = 2 km per trip

Divide total distance by distance per trip:

348 km / 2 km per trip = 174 trips

Answer: 174 trips

5 0
3 years ago
What is the product 3x5(2x2+4x+1)
lesya692 [45]

Answer:

6x^7+12x^6+3x^5

Step-by-step explanation:

The given expression is:

3x^5(2x^2+4x+1)

We expand the parenthesis using the distributive property to obtain;

3x^5(2x^2)+3x^5(4x)+3x^5(1)

Recall that;

a^m\imes a^n=a^{m+n}

We apply this property and multiply out the constant terms to obtain;

6x^7+12x^6+3x^5

3 0
3 years ago
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