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solmaris [256]
3 years ago
12

Create a static method called fillArray, which takes an integer array as an input parameter, along with an integer initial value

. It should then fill the array with values starting from the initial value, and counting up by 1s. For example, if the data array has length 5, and if the initialValue is 3, then after execution the array should hold this sequence: 3 4 5 6 7. public static void fillArray (int[] data, int initialValue) {
Computers and Technology
1 answer:
JulijaS [17]3 years ago
3 0

Answer:

public class print{

   

   public static void fillArray(int[] arr, int initialValue){

       

       int n = arr.length;

      for(int i=0;i<n;i++){

          arr[i] = initialValue++;

      }

       for(int i=0;i<n;i++){

           System.out.print(arr[i]+" ");

      }

       

   }

    public static void main(String []args){

       

        int[] array = new int[5];

        int initialValue =3;

       

        fillArray(array,initialValue);

       

    }

}

Explanation:

Create the function with two parameter first is array and second is integer.

Then, declare the variable and store the size of array.

Take the for and fill the array from the incremented value of initialValue  by 1 at every run of loop.

After loop, print the element of the array.

Create the main function which is used for calling the function and also declare the array with size 5 and initialValue with 3. After that, call the function with this argument.

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In this exercise you will debug the code which has been provided in the starter file. The code is intended to do the following:
abruzzese [7]

Answer:

The corrected code is as follows:

import java.util.Scanner;

public class U2_L4_Activity_Two{

public static void main(String[] args){

Scanner scan = new Scanner(System.in);

String str1 = scan.nextLine();

String str2 = str1;

str1 = str1.toUpperCase();

System.out.println(str1);

System.out.println(str2);

}

}

Explanation:

This corrects the scanner object

Scanner scan = new Scanner(System.in);

This line is correct

String str1 = scan.nextLine();

This copies str1 to str2

String str2 = str1;

This converts str1 to upper case

str1 = str1.toUpperCase();

This prints str1

System.out.println(str1);

This prints str2

System.out.println(str2);

8 0
3 years ago
What is a sound wave
solmaris [256]

Answer:

A wave of sound!

Explanation:

sound waves are sound but sound comes in different wavelengths

7 0
3 years ago
Read 2 more answers
You are informed that all the users within the network are unable to access the Internet. You decide to start troubleshooting fr
sveticcg [70]

Answer: Bottom up approach

Explanation:

We should start from the bottom i.e.starting from the physical layer by inspecting the lan, switches, router and also as we move up the level we also need to check the software application and the various routing protocols at each successive levels.

Hence, we use bottom up approach.

3 0
3 years ago
How do you do this question?
laila [671]

Answer:

(a) 1 to 8

(b) 1 to 6

Explanation:

A "leaf" is a node at the end of a binary tree (in other words, it has no "children").  All other nodes are "non-leaf" nodes.

The smallest number of leaves is 1.  That would be a binary tree that's just a straight line; each node will have only 1 child, until you get to the last node (the leaf).

To find the largest number of leaves, we start drawing a full binary tree.  A complete tree with 15 nodes has 7 non-leaf nodes and 8 leaf nodes.  A full tree with 6 non-leaf nodes can have up to 6 leaf nodes.

6 0
3 years ago
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Implement function easyCrypto() that takes as input a string and prints its encryption
jasenka [17]

Answer:

The program written in python is as follows;

import string

def easyCrypto(inputstring):

      for i in range(len(inputstring)):

             try:

                    ind = string.ascii_lowercase.index(inputstring[i])

                    pos = ind+1

                    if pos%2 == 0:

                           print(string.ascii_lowercase[ind-1],end="")

                    else:

                           print(string.ascii_lowercase[ind+1],end="")

             except:

                    ind = string.ascii_uppercase.index(inputstring[i])

                    pos = ind+1

                    if pos%2 == 0:

                           print(string.ascii_uppercase[ind-1],end="")

                    else:

                           print(string.ascii_uppercase[ind+1],end="")

anystring = input("Enter a string: ")

easyCrypto(anystring)

Explanation:

The first line imports the string module into the program

import string

The functipn easyCrypto() starts here

def easyCrypto(inputstring):

This line iterates through each character in the input string

      for i in range(len(inputstring)):

The try except handles the error in the program

             try:

This line gets the index of the current character (lower case)

                    ind = string.ascii_lowercase.index(inputstring[i])

This line adds 1 to the index

                    pos = ind+1

This line checks if the character is at even position

                    if pos%2 == 0:

If yes, it returns the alphabet before it

                           print(string.ascii_lowercase[ind-1],end="")

                    else:

It returns the alphabet after it, if otherwise

                           print(string.ascii_lowercase[ind+1],end="")

The except block does the same thing as the try block, but it handles uppercase letters

<em>              except: </em>

<em>                     ind = string.ascii_uppercase.index(inputstring[i]) </em>

<em>                     pos = ind+1 </em>

<em>                     if pos%2 == 0: </em>

<em>                            print(string.ascii_uppercase[ind-1],end="") </em>

<em>                     else: </em>

<em>                            print(string.ascii_uppercase[ind+1],end="") </em>

<em />

The main starts here

This line prompts user for input

anystring = input("Enter a string: ")

This line calls the easyCrypto() function

easyCrypto(anystring)

4 0
3 years ago
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