Question

(50 points) Write a program arrays1.cthat checks if two integer arrays are different by one and only one elementwhen compared element by element (first element with first element, second with second, and so on)and displays theelements that are different. The program asks the user to enter the size of the arrays and then the elements of the arrays.

Answer 1

Answer:

#include<stdio.h>

int one_element_different(int *a1 ,int *a2 ,int n ,int *element1 ,int *element2) { for (int k=0;k<n;k++) {

if(*a1!=*a2)

return k;

else { a1++; a2++; } }

return 0;

} int main() {

int n;

printf("Enter the length of the array \n");

scanf("%d",&n); int a1[n],a2[n];  

printf("Enter the elements of first array");

for (int i=0;i<n;i++) {

scanf("%d",&a1[i]);

}

printf("\nEnter the elements of second array ");

for (int j=0;j<n;j++)

{

scanf("%d",&a2[j]);

}

int result = one_element_different( a1 ,a2 ,n ,a1 ,a2);

if(result) {

printf("\nArray are Different by one element at %d %d \n ", a1[result], a2[result]);

}

else {

printf("\nArray are NOT Different by one element \n");

}

}

Explanation:

• Compare each element and if there is any mismatch, return the position of that element otherwise return 0.
• Get the size from user.
• If the result has True value, display the message that array are different by one element.