Answer:
#include<stdio.h>
int one_element_different(int *a1 ,int *a2 ,int n ,int *element1 ,int *element2) { for (int k=0;k<n;k++) {
if(*a1!=*a2)
return k;
else { a1++; a2++; } }
return 0;
} int main() {
int n;
printf("Enter the length of the array \n");
scanf("%d",&n); int a1[n],a2[n];
printf("Enter the elements of first array");
for (int i=0;i<n;i++) {
scanf("%d",&a1[i]);
}
printf("\nEnter the elements of second array ");
for (int j=0;j<n;j++)
{
scanf("%d",&a2[j]);
}
int result = one_element_different( a1 ,a2 ,n ,a1 ,a2);
if(result) {
printf("\nArray are Different by one element at %d %d \n ", a1[result], a2[result]);
}
else {
printf("\nArray are NOT Different by one element \n");
}
}
Explanation:
- Compare each element and if there is any mismatch, return the position of that element otherwise return 0.
- Get the size from user.
- If the result has True value, display the message that array are different by one element.
