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k0ka [10]
3 years ago
6

X + 6.8 = 12.19. What is x?

Mathematics
1 answer:
alina1380 [7]3 years ago
6 0

Answer:

<h2>x = 5.39</h2>

Step-by-step explanation:

x + 6.8 = 12.19            <em>subtract 6.8 from both sides</em>

x + 6.8 - 6.8 = 12.19 - 6.8

x = 5.39

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Step-by-step explanation:

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Pls pls help me I will mark you brainest
Firlakuza [10]

Answer:

55

Step-by-step explanation:

7 x 10 = 70

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4 0
3 years ago
Let X have the probability mass function P(X = −1) = 1 2 , P(X = 0) = 1 3 , P(X = 1) = 1 6 Calculate E(|X|) using the approaches
Studentka2010 [4]

Answer:

Step-by-step explanation:

From the given information:

Note that the possible values of Y are 0 and 1 because;

y = 0 if X = 0 and y = 1 if X = ±1

∴

P(Y =0) = P(X = 0) =\dfrac{1}{3}

P(Y = 1) = P(X = -1  \ or \ 1) \\ \\ = P(X = -1) + P(X = 1)

= \dfrac{1}{2}+ \dfrac{1}{6}

=\dfrac{3+1}{6}

= \dfrac{2}{3}

b)

E(|X|) = \sum |x| P(X=x) = ( 1 \times \dfrac{1}{2}) + ( 0\times \dfrac{1}{3}) + ( 1 \times \dfrac{1}{6})

= \dfrac{2}{3}

7 0
3 years ago
Find the slope and y intercept, convert to slope intercept form<br><br> 3x + 12y = 12
xenn [34]

Answer:

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Step-by-step explanation:

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3 0
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This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
ANTONII [103]

Answer:

Maximum value: 3* \sqrt{n}

Minimum value: -3* \sqrt{n}

Step-by-step explanation:

Let g(x) = x_1^2 + x_2^2+x_3^2+ ----+ x_n^2 , the restriction function.The Lagrange Multiplier problem states that an extreme (x1, ..., xn) of f with the constraint g(x) = 9 has to follow the following rule:

\nabla{f}(x_1, ..., x_n) = \lambda \nabla{g} (x_1,...,x_n)

for a constant \lambda .

Note that the partial derivate of f respect to any variable is 1, and the partial derivate of g respect xi is 2xi, this means that

1 = \lambda 2 x_1

Thus,

x_i = \frac{1}{2\lambda} = c

Where c is a constant that doesnt depend on i. In other words, there exists c such that (x1, x2, ..., xn) = (c,c, ..., c). Now, since g(x1, ..., xn) = 9, we have that n * c² = 9, or

c = \, ^+_- \, \sqrt{\frac{9}{n} } = \, ^+_- \frac{3}{\sqrt{n}}

When c is positive, f reaches a maximum, which is \frac{3}{\sqrt{n}}  +  \frac{3}{\sqrt{n}} +  \frac{3}{\sqrt{n}}  + ..... +  \frac{3}{\sqrt{n}}  = n *  \frac{3}{\sqrt{n}}  = 3 * \sqrt{n}

On the other hand, when c is negative, f reaches a minimum, -3 * \sqrt{n}

8 0
4 years ago
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