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3 years ago

Which of the following is the graph of y=sqr root -x-3

Mathematics

1 answer:

Elan Coil [88]3 years ago

3 0

Answer:

The graph in the attached figure

see the explanation

Step-by-step explanation:

we have

$y=\sqrt{-x-3}$

we know that

The radicand must be greater than or equal to zero

$(-x-3)\geq 0$

solve for x

Adds 3 both sides

$-x\geq 0+3$

$-x\geq 3$

Multiply by -1 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$x\leq -3$

The domain of the function is the interval (-∞,-3]

For x=-3 ---> the value of y=0

The range is the interval {0,∞)

therefore

The graph in the attached figure

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B. A'(5) = 1.76 cm/s

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A. Area of a circle is given by

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So to find the rate of the area:

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Multipying and simplifying:

$\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$

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$A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}$

$A'(5)=\frac{2408693760\pi}{4294967296}$

$A'(5)=1.76268$

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