Question

Suppose a team is to be formed consisting of a head chef, sous chef, and dishwasher, in that order. What is the probability of forming such a team with 6 people?

Answer 1

Answer:

0.0083

Step-by-step explanation:

From the given information;

The total number of individual in the team = 3

The number of ways the team, which comprises of head chef, sous chef, and dishwasher can be arranged = $^{6}P_3$

= (6×5×4×3!)/3!

= 6×5×4

= 120 ways

The probability of forming such a team with 6 people = 1/120

= 0.0083