Solve for x by finding the missing side of the triangle. Round your answer to the nearest tenth.

Mathematics

1 answer:

MAXImum [283]3 years ago

4 0

Answer:

Step-by-step explanation:

Tangent θ = Opposite / Adjacent

tan(29) = 20/x

Cross multiply.

x = 20 / (tan(29))

x = 22.544284

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A line passes through the point (–2, 7) and has a slope of –5. What is the value of a if the point (a, 2) is also on the line?

never [62]

(x1,y1) = (-2,7)
m = -5
(x,y) = (a,2)

Forming the equation,
(y-y1) = m(x-x1)
y - 7 = -5[x - (-2)]
y - 7 = -5x - 10
y + 5x = -3

Putting the values of (x,y) we get,
2 + 5a = -3
5a = -5
a = -1

8 0

4 years ago

Read 2 more answers

A)Which would you use to solve the following system and why?

posledela

A
I would choose the first system to stay the same because it would easier to multiply than divide (something along those lines)
b
if you choose the first system) you would multiply the 2nd equation by a -5

3 0

3 years ago

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

<u>Step-by-step explanation:</u>

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$