1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
katen-ka-za [31]
3 years ago
5

15. You bought a magazine for $2 and some candy bars for $5 each. You spent a total of $12. How

Mathematics
2 answers:
mart [117]3 years ago
6 0

Answer: 2 candy bars

Step-by-step explanation:

shutvik [7]3 years ago
3 0

Answer:

2 candy bars

Step-by-step explanation:

2x+5x=12

so easy way to look at this is using 1 for 2

because you bought A magazine which is 1

2(1)+5x=12

2+5x=12

we know 2+5 is 7 so lets try 2!

2+5(2)=12

2+10=12

12=12

And there you go!

The answer is 2

You might be interested in
Which expression represents the following calculation?
____ [38]

Answer:

(381-22)*16

Step-by-step explanation:

(381-22)*16

3 0
4 years ago
Read 2 more answers
Which expression would you use to find the number of outcomes for flipping 4 coins?
Papessa [141]
The answer would be 2(4)
3 0
3 years ago
Read 2 more answers
Does the Commutative Property of Addition apply when you add two negative integers?
MAVERICK [17]

The commutative property of addition means we can add two integers in any order. So yes, It would still apply to two negative integers (for example, -2 + -3 and -3 + -2 both equal five)

4 0
4 years ago
Please help!! Will give brainliest
MariettaO [177]

Answer:

I think its the second answer chose

Step-by-step explanation:

I hope this helps! Have a nice day! Owa Owa!

6 0
3 years ago
Suppose x, y and z are integers. Prove that, if 3x−y + 5z is even, then at least one of x, y or z is even.
Elden [556K]

Given:

x, y and z are integers.

To prove:

If 3x-y+5z is even, then at least one of x, y or z is even.

Solution:

We know that,

Product of two odd integers is always odd.          ...(i)

Difference of two odd integers is always even.          ...(ii)

Sum of an even integer and an odd integer is odd.      ...(iii)

Let as assume x, y and z all are odd, then 3x-y+5z is even.

3x is always odd.          [Using (i)]

5z is always odd.          [Using (i)]

3x-y is always even.       [Using (ii)]

(3x-y)+5z is always odd.       [Using (iii)]

3x-y+5z is always odd.

So, out assumption is incorrect.

Thus, at least one of x, y or z is even.

Hence proved.

4 0
3 years ago
Other questions:
  • What is the fraction 1 over 6 as a percent?
    13·2 answers
  • A number n divided by 4
    8·2 answers
  • Nadia make the diagram below to represent the counter space she wants to build in her craft room
    12·1 answer
  • Find the product of 4 (78 + 3).
    11·2 answers
  • Stuck with a current word problem
    7·1 answer
  • What is the volume of the rectangular prism below?
    9·1 answer
  • Can y’all please help me with these 3 question for Math class
    10·2 answers
  • Eighth grade<br> &gt;<br> A.2 Divisibility rules<br> Is 932,920 divisible by 4?<br> Yes or no
    10·2 answers
  • Hi there. Pls help me. Also the question is too long to type um so i took screenshot. Ty if u solved it and showed me how to do
    11·2 answers
  • Oh, boy! Look at that monthly payment from Question 2 above! Molly cannot afford the monthly payment using the 0% financing. She
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!