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mezya [45]
3 years ago
13

What is the simplified form of this expression 7(^3sqrt2x)-3(^3sqrt16x)-3(^3sqrt8x)

Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0

Answer:

<h2>7 \sqrt[3]{2x}  - 6 \sqrt[3]{2x}  - 6x</h2>

Solution,

7( \sqrt[3]{2x} ) - 3( \sqrt[3]{16x} ) - 3( \sqrt[3]{8x} ) \\  = 7 \sqrt[3]{2x}  - 3 \times ( \sqrt[3]{2 \times 2 \times 2 \times 2x}  - 3 \times  \sqrt[3]{2 \times 2 \times 2x}  \\  = 7 \sqrt[3]{2x}  - 3 \times (2 \sqrt[3]{2} x) - 3 \times 2x \\  = 7 \sqrt[3]{2x}  - 3 \times 2 \times  \sqrt[3]{2x}  - 3 \times 2x \\  = 7 \sqrt[3]{2x}  - 6 \sqrt[3]{2x}  - 6x

Hope this helps...

Good luck on your assignment...

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Given the equation startfraction 2 x 2 over y endfraction = 4 w 2 what is the value of x? x = y w y minus 1 x = 2 y w y minus 1
Leona [35]

The value of x is 2yw + y - 1 for the given equation 2x + 2/y = 4w + 2.

According to the given question.

We have an equation

2x + 2/y = 4w + 2

Since, we have to find the value of x for the given equation

2x + 2/y = 4w + 2

Thereofore,

2x + 2/y = 4w + 2

⇒ 2(x + 1)/y = 2(2w + 1)    (taking 2 common from both the sides)

⇒ (x + 1)/y = 2w + 1

⇒ (x + 1) = y(2w + 1)         (multiplying both the sides by y)

⇒ x + 1 = 2yw + y

⇒ x = 2yw + y - 1         ( subtracting 1 both the sides)

Hence, the value of x is 2yw + y - 1 for the given equation 2x + 2/y = 4w + 2.

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5 0
2 years ago
Can someone help me plz??
Brut [27]

Answer:

96π

Step-by-step explanation:

v =  \frac{1}{3}  {r}^{2} h\pi

V=96π

5 0
3 years ago
Let a and b be positive integers. 23^a x 23^b
Ket [755]

Answer:

23 ^ ( a+b)

Step-by-step explanation:

23^a *23^b

Since the bases are the same, we can add the exponents

23 ^ ( a+b)

6 0
3 years ago
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From a point p on level ground, the angle of elevation of the top of a tree is 60°. If the tree is 39m high, how far is its base
zzz [600]
Hello,

tan 60°=√3
d/39=tan 60°==>d=39/√3=39√3/3=13√3=22,516660498... (m)

5 0
3 years ago
What type(s) of symmetry does this figure have?
kirza4 [7]
It's for sure reflection symmetry, I think it's also point reflection (the point must be in the very middle of the figure). I hope it will help you somehow :)
3 0
3 years ago
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