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ikadub [295]
3 years ago
8

Can anyone help me on this?

Mathematics
1 answer:
fgiga [73]3 years ago
5 0
The answer is 3.142 your welcome
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ASAP HELP!!! use the quadratic regression feature of a graphing calculator to find a quadratic model. round to the nearest thous
seropon [69]

Answer:

y = 0.008x^2 + 0.518x + 131.886

Step-by-step explanation:

  1. Make sure your Plot 1 is ON. Select the Scatter Plots and the appropriate lists.
  2. Clear all functions in [Y=]
  3. Input data in L1 and L2. Go to [Stat] [Enter] to input data.
  4. Graph data points. ...
  5. Choose a regression from the list in [Stat] "CALC". ...
  6. Go to [ZOOM] "9: ZoomSTat" to view the data with the regression curve.

(credit: CPM Educational Program)

3 0
3 years ago
6x+9=-12<br> Can someone help me with this question
Amiraneli [1.4K]

Answer:

-7/2

Step-by-step explanation:

6 0
3 years ago
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Need help asap!! !! !!
garri49 [273]

Answer:

18

Step-by-step explanation:

since U is the midpoint of QT, QT = 2(QU)

similarly, QS = 2 (QR)

because QR is parallel to QS and QU is parallel to QT, triangle QUR is similar to triangle QTS. therefore, the scaling factor between QT/QU and QS/QR is equal to the scaling factor between RU and ST.

therefore,

ST  = 2(RU)

36 = 2(RU)

18 =RU

3 0
3 years ago
triangle is placed in a semicircle with a radius of 8cm, as shown below. Find the area of the shaded region. Use the value 3.14
zhuklara [117]

Answer:

Area of shaded region is 36.48 \ cm^2.

Step-by-step explanation:

We have drawn the diagram for your reference.

Given:

radius = 8 cm

Diameter is 2 times radius.

Diameter = 2\times 8 =16 \ cm

We need to find the Area of shaded region.

Solution:

First we will find the Area of Semicircle.

Now we know that Area of semicircle is half times π times square of radius.

framing in equation for we get;

Area of Semicircle = \frac{1}{2} \times \pi \times r^2 = \frac{1}{2} \times \pi \times 8^2=100.48\ cm^2

Now we will find the Area of Triangle.

Now base diameter of the semicircle and height is radius of the circle.

We know that Area of triangle is half times base times height.

framing in equation form we get;

Area of triangle = \frac{1}{2} \times 16 \times 8 = 64 \ cm^2

Now Area of the shaded region can be calculated by subtracting Area of triangle from Area of semicircle.

framing in equation form we get;

Area of the shaded region = 100.48 - 64 = 36.48 \ cm^2

Hence Area of shaded region is 36.48 \ cm^2.

6 0
3 years ago
Given that A'B'C' is the image of ABC under a reflection, enter that equation of the line of reflection.
PolarNik [594]

Answer:

sooooo

Step-by-step explanation:

7 0
3 years ago
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