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Dmitrij [34]
3 years ago
5

What is y=2/3+4 written in standard form

Mathematics
1 answer:
zavuch27 [327]3 years ago
3 0
On this problem the answer will be 2X-3y= -12
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The outside of an aquarium tank is 50 cm long, 40 cm wide, and 20 cm high. It is open at the top. The glass used to make the tan
zepelin [54]
We know that

[<span>inside volume of the tank]=[40-2]*[50-2]*[20-1]------> (the top is open)
</span>[inside volume of the tank]=[38]*[48]*[19]----> 34656 cm³

the answer is
the inside volume of the tank is 34656 cm³
3 0
3 years ago
Your cousin borrows $1125 to repair her car. The simple annual interest rate is 10%. She makes equal monthly payments of $25. Ho
stepan [7]

Answer:

Step-by-step explanation:

Your cousin borrows $1125 to repair her car. The simple annual interest rate is 10%. She makes equal monthly payments of $25. How many years will it take to pay off the loan? (PLSSS HELP)

Given data

P=$1125

R=10%= 0.1

I= $25

We know that

I=PRT

5 0
3 years ago
June served 4/9 of fruit punch.how many liters does she have left
Sladkaya [172]
Just take 9/9-4/9=5/9, we get 9/9 because that is how much fruit punch that there was when the container was full. Enjoy!=)
8 0
3 years ago
Read 2 more answers
Use a division ladder to find the gcf of 20 and 50.
Usimov [2.4K]

Gcf refers to a digit which can divide both numbers without a remainder
20|50 is divisible by 2 to become 10|25 and then divisible by 5 to become 2|5
=2×5
Gcf= 10
5 0
3 years ago
Each unit in the coordinate plane corresponds to 1 mile. Find the distance from the school to Cherry Street. Round your answer t
GarryVolchara [31]

Answer:

11.2

Step-by-step explanation:

We can use the distance formula to solve this problem.

This distance formula states that the distance between two points (x_1, y_1) and (x_2,y_2) is equal to \sqrt{(\Delta x)^2+(\Delta y)^2}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

School is at coordinate point (9,6) and the closest point to school on Cherry St. is (4,-4).

Thus, the distance between school and Cherry Street is \sqrt{(9-4)^2+(6-(-4))^2}=\sqrt{5^2+10^2}=\sqrt{125}=5\sqrt{5}\approx \boxed{11.2}

3 0
3 years ago
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