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ikadub [295]
3 years ago
7

What’s the unit rate of y = 6x

Mathematics
1 answer:
asambeis [7]3 years ago
8 0

Answer:

i dont know

Step-by-step explanation:

sorry i just need pionts

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Which equation has infinitely many solutions?
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10x-5y=25 solve for y
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<span>10x-5y=25 solve for y
so
10x - 5y = 25
5y = 10x - 25
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hope it helps</span>
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Jasmine needs to reduce the height of a picture from five inches to two inches so it will fit in the yearbook. What percentage o
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The equation of the line in standard form is...
Rudik [331]

Answer:

5x+9y=-16

Step-by-step explanation:

here is my work although I am not 100 percent sure I am right because,I am learning the same thing as you

-6+1 over 4+5

y+1=-5/9(x+5)

y+1=-5/9x-25/9

y=-5/9x-16/9

5/9+y=-16/9

5x+9y=-16

8 0
3 years ago
Read 2 more answers
Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3
Whitepunk [10]

If f(x)=4x-3:

\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4

If f(x)=4x^{-3}:

\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}

\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}

\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}

7 0
4 years ago
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