<h3>y = x + 20</h3><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>
Answer:
8/5
Step-by-step explanation:8/5
well, rational = fractional, namely something you can write as a fraction, well, anything between -1 and -2 is just less than -1 so

Answer:
B. No

Step-by-step explanation:
-A right angle triangle has two complimentary acute angles and one right angle.
-
is usually one of the acute angles and is equivalent to 90º minus it's complimentary acute angle.
-Complimentary angles add up to 90º.
#For complimentary angles:

The two acute angles cannot have the same Cosine value.
Hence, she's not correct.
You know that 7*7 is 49, and 6*6 is 36. Now you know it will be 6._. 6*7 is 42, so think of that as 6.5^2. You know that it will most likely be less than 6.8 since it is so close to being 7*7, which is 4 above your desired number. This leaves 6.6 to 6.8 as your estimate. Personally, I would go straight in the middle and choose 6.7.
I hope this helps!