Answer:
![\left[\begin{array}{cc}2&0\\-2&3\end{array}\right]+\left[\begin{array}{cc}1&5\\0&1\end{array}\right]=\left[\begin{array}{cc}3&5\\-2&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%260%5C%5C-2%263%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%265%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C-2%264%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
If you have two matrices:
![A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%5C%5Cand%5C%5CB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7De%26f%5C%5Cg%26h%5Cend%7Barray%7D%5Cright%5D)
The sum of the matrices is:
![A+B=\left[\begin{array}{cc}a+e&b+f\\c+g&d+h\end{array}\right]](https://tex.z-dn.net/?f=A%2BB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%2Be%26b%2Bf%5C%5Cc%2Bg%26d%2Bh%5Cend%7Barray%7D%5Cright%5D)
In this case we have:
![A=\left[\begin{array}{cc}2&0\\-2&3\end{array}\right]\\\\\\B=\left[\begin{array}{cc}1&5\\0&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%260%5C%5C-2%263%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5C%5CB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%265%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
The <u>sum</u> is:
![A+B=\left[\begin{array}{cc}2+1&0+5\\-2+0&3+1\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}3&5\\-2&4\end{array}\right]](https://tex.z-dn.net/?f=A%2BB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%2B1%260%2B5%5C%5C-2%2B0%263%2B1%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5C%5CA%2BB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C-2%264%5Cend%7Barray%7D%5Cright%5D)
The answer is:
![\left[\begin{array}{cc}2&0\\-2&3\end{array}\right]+\left[\begin{array}{cc}1&5\\0&1\end{array}\right]=\left[\begin{array}{cc}3&5\\-2&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%260%5C%5C-2%263%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%265%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%265%5C%5C-2%264%5Cend%7Barray%7D%5Cright%5D)
Carry on... There is not sufficient information to answer
Answer:
57.6°
Step-by-step explanation:
It is always helpful to draw a picture. Also, you need to memorize all the definitions of the trig functions. For example,
sine of an angle = opposite side/hypotenuse
In your case, SQ is opposite side to angle R and QR is the hypotenuse
Therefore, sin R = 6.5/7.7
m∠R = arcsin (6.5/7.7) = 57.6°
The hundredth number in the series as defined in the task content is; 107.
<h3>What is the 100th Number?</h3>
According to the task content;
The first term of the sequence of numbers is; 8 and evidently, the common difference of the sequence is; 9-8 = 1.
On this note it follows that the 100th number is;
T(100th). = 8 + 99(1) = 107.
Read more on terms in sequence;
brainly.com/question/7882626
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