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3 years ago

7

A cube has volume of 8 cubic inches. what is the length of each of the cube?

1 answer:

schepotkina [342]3 years ago

4 0

Answer:

2

Step-by-step explanation:

2x2x2x2 is 8

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What is the value of x

My name is Ann [436]

X=3

Explanation:

A straight line equals 180°, and they give you the one angle of 56°, so you know 56+ the other equation has to equal 180

56+4x+112=180
168+4x=180

Subtract 168 from both sides

4x=12

Divide 4 from both sides

X=3

You can check by filling it in.

56+4*3+112=

12+56+112=180

5 0

3 years ago

Drag each equation to show if it could be a correct first step to solving the equation

Vlad [161]

Tell me what the answer

4 0

3 years ago

Read 2 more answers

a box of cereal contains 23.4 ounces. It cost $5.49. What is the cost,to the nearest cent, of the cereal per ounce.

anyanavicka [17]

Do 5.49 / 23.4
This equals $0.23

The answer is $0.23

5 0

3 years ago

What is the solution to the inequality -6( p - 8) < -12?

coldgirl [10]

Answer:

p > 10

Step-by-step explanation:

Given

- 6(p - 8) < - 12

Divide both sides by - 6, reversing the symbol as a result of dividing by a negative quantity.

p - 8 > 2 ( add 8 to both sides )

p > 10

3 0

3 years ago

Read 2 more answers

A veterinarian wants to know if pit bulls or golden retrievers have a higher incidence of tooth decay at the age of three. The v

BigorU [14]

Answer: B) [-0.0332,0.1332]

Step-by-step explanation: <u>Confidence</u> <u>Interval</u> is an interval where we can be a percentage sure the true mean is.

The confidence interval for a difference in population proportion is calculated following these steps:

First, let's find population proportion for each population:

$p_{1}=\frac{30}{120}=0.25$

$p_{2}=\frac{32}{160}=0.2$

Second, calculate standard deviation for each proportion:

$\sigma_{1}=\sqrt{\frac{0.25(0.75)}{120} } = 0.0395$

$\sigma_{2}=\sqrt{\frac{0.2(0.8)}{160} } = 0.0316$

Now, we calculate standard error for difference:

$SE=\sqrt{\sigma_{1}^{2}+\sigma_{2}^{2}}$

$SE=\sqrt{0.0395^{2}+0.0316^{2}}$

SE = 0.0505

The z-score for a 90% CI is 1.645.

Then, confidence interval is

$p_{1}-p_{2}$ ± z-score.SE

$0.25-0.2$ ± $1.645(0.0505)$

0.05 ± 0.0831

The limits of this interval are:

inferior: 0.05 - 0.0831 = $-0.0332$

superior: 0.05 + 0.0831 = 0.1332

The 90% confidence interval for the difference in the population proportion of pit pulls and golden retrievers is $[-0.0332,0.1332]$ .

8 0

3 years ago