All categories

3 years ago

A cube has volume of 8 cubic inches. what is the length of each of the cube?

Mathematics

1 answer:

schepotkina [342]3 years ago

4 0

Answer:

Step-by-step explanation:

2x2x2x2 is 8

You might be interested in

Doing a test please help

Ainat [17]

Answer:

The answer is C

Step-by-step explanation:

Hope this helps.

3 0

3 years ago

Read 2 more answers

Write a rule to describe the function shown.

I am Lyosha [343]

Answer:

y = -3x

Step-by-step explanation:

(a) Slope

y = mx + b

Choose points (-3, 9) and (3, -9)

m = (-9 - 9)/(3 – (-3))

m = -18/(3 + 3)

m = -18/6

m = -3

=====

(b) y-intercept

y = mx +b

Choose point (0,0).

0 = 0 + b

b = 0

=====

(c) Equation of line

y = mx + b

y = -3x

6 0

3 years ago

Two angles are supplementary. The larger angle is 33 degrees more than 6 times the smaller angle. Find the measure of each angle

noname [10]

Sum of two angles that are supplementary = 180°

Let the smaller angle be = x

$Let \: the \: smaller \: angle \: be \: = \: x$

$then \: the \: larger \: angle \: = 6x + 33$

<h3>Their sum :</h3>

$x + 6x + 33 = 180$

$7x + 33 = 180$

$7x = 180 - 33$

$7x = 147$

$x = \frac{147}{7}$

$x = 21$

Using this let us find the measures of the smaller angle and bigger angle .

$smaller \: angle \: = x = 21°$

$larger \: angle \: = 6x + 33 = 6 \times 21 + 33 = 126 + 33 = 159°$

∴ The measure of the two angles are = 21° and 159° .

3 0

3 years ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

Hence, the midpoint of the segment is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

6 0

3 years ago

Factories 12x-30 please help me

Luden [163]

Answer:

6(2x - 5)

Step-by-step explanation:

The greatest common factor of 12x and 30 is 6.

12x - 30 = 6(2x - 5)

8 0

3 years ago

Read 2 more answers