I don’t know about the slope but the Y-Intercept is just the Y.
Answer:
For the first one the answer is:
<K = 31°
Sorry I don't know the second one.
Answer:
(a) x = -2y
(c) 3x - 2y = 0
Step-by-step explanation:
You can tell if an equation is a direct variation equation if it can be written in the format y = kx.
Note that there is no addition and subtraction in this equation.
Let's put these equations in the form y = kx.
(a) x = -2y
- y = x/-2 → y = -1/2x
- This is equivalent to multiplying x by -1/2, so this is an example of direct variation.
(b) x + 2y = 12
- 2y = 12 - x
- y = 6 - 1/2x
- This is not in the form y = kx since we are adding 6 to -1/2x. Therefore, this is <u>NOT</u> an example of direct variation.
(c) 3x - 2y = 0
- -2y = -3x
- y = 3/2x
- This follows the format of y = kx, so it is an example of direct variation.
(d) 5x² + y = 0
- y = -5x²
- This is not in the form of y = kx, so it is <u>NOT</u> an example of direct variation.
(e) y = 0.3x + 1.6
- 1.6 is being added to 0.3x, so it is <u>NOT</u> an example of direct variation.
(f) y - 2 = x
- y = x + 2
- 2 is being added to x, so it is <u>NOT</u> an example of direct variation.
The following equations are examples of direct variation:
Answer:
150+50*4=350
Step-by-step explanation:
hope it helped sorry if it's not what you wanted.
Answer:
Step-by-step explanation:
dy/dx= -(2x+3y+1)/(3x-2y+1)
Let x= X+p. and y = Y+q. then dy/dx = dy/dX.
dy/dX= -(2X+2p+3Y+3q+1)/(3X+3p-2Y-2q+1) =
dy/dX = -{2X+3Y+(2p+3q+1)}/{3X-2Y+(3p-2q+1)}
Now 2p+3q+1=0……………..(1)
3p-2q +1=0…………………………(2)
p/(3+2)=q/(3–2)=1/(-4–9)