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soldi70 [24.7K]
3 years ago
7

If g(x)=x^2-4 find g(5)

Mathematics
2 answers:
spin [16.1K]3 years ago
7 0
Put 5 instead of x
g(5)=5^2-4=21
Fudgin [204]3 years ago
6 0

Answer:

<h2>21</h2>

Step-by-step explanation:

g(x)=x^2-4\\\\g(5)-\text{put}\ x=5\ \text{to the equation of the function}\ g(x):\\\\g(5)=5^2-4=25-4=21

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Answer:

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Step-by-step explanation:

4x = 32 - x2 would be much clearer if written as 4x = 32 - x^2.  Please use

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Rewrite 4x = 32 - x^2 in the standard form of a quadratic:  x^2 + 4x - 32

Then the coefficients are a = 1, b = 4 and c = -32.

Find the discriminant.  It is b^2-4ac.  

Here, b^2-4ac = 4^2 - 4(1)(-32), or 16 + 128, or 144.

Because the discriminant is positive, we know immediately that this quadratic has two real, unequal roots.

So, the answer to this question is "the graph of 4x = 32 - x^2 cross the x-axis in two places."

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