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3 years ago

Anyone know quadratics

Mathematics

1 answer:

VMariaS [17]3 years ago

3 0

When competing the square, you want to have
${b}^{2}$
at the end, and using the fact that the x term and coefficient are really
$2bx$
, we see that the third option is the most efficient way to start

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Perform the indicated operation.(3/a+2) + (4/a-5)

kipiarov [429]

Answer:

$\frac{7(a-1)}{(a+2)(a-5)}$

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

$\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}$

Thus, the solution is 7(a -1) / (a+2)(a-5)

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4 years ago

The archery club competed in a tournament. Each archer shot 6 arrows in 5 minutes.

stira [4]

Answer:

Step-by-step explanation:

8 0

1 year ago

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At the beginning of 2072, the population of a city was 50,000. If annual If the population growth rate is 10%, what will be the

Naddik [55]

Answer:

60,500

Step-by-step explanation:

50000 $(1+.1)^{t}$

50000 $(1+.1)^{2}$

60,500

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3 years ago

The following function is probability mass function. f left-parenthesis x right-parenthesis equals StartFraction 2x plus 1Over 2

lora16 [44]

Answer:

a) Mean = 2.6

B) Variance = 9.2

Step-by-step explanation:

We are given the following probability mass function in the question:

$F(x) = \dfrac{2x+1}{25}, x = 0,1,2,3,4$

a) Mean of random variable

$\mu = \displaystyle\sum x_iF(x_i)\\\\=0(\dfrac{1}{25}) + 1(\dfrac{2+1}{25}) + 2(\dfrac{4+1}{25}) + 3(\dfrac{6+1}{25}) + 4(\dfrac{8+1}{25})\\\\=\dfrac{3+10+21+36}{25} = \dfrac{70}{25} = 2.8$

b) Variance of the random variable

$\sigma^2 = \displaystyle\sum x_i^2F(x_i)\\\\=0^2(\dfrac{1}{25}) + 1^2(\dfrac{2+1}{25}) + 2^2(\dfrac{4+1}{25}) + 3^2(\dfrac{6+1}{25}) + 4^2(\dfrac{8+1}{25})\\\\=\dfrac{3+20+63+144}{25} = \dfrac{230}{25} = 9.2$

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3 years ago

PLEASE ANSWER AND EXPLAIN | 98 POINTS

Tema [17]

Answer:

The answer is C.

Step-by-step explanation:

When we see something with a high correlation coefficient, we know that these two things trend in the same direction (which eliminates D). However, we must remember that correlation does not mean causation, so A and B are also out.

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3 years ago

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