<img src="https://tex.z-dn.net/?f=%5Csqrt%7B-64%7D" id="TexFormula1" title="\sqrt{-64}" alt="\sqrt{-64}" align="absmiddle" class

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Yuki888 [10]

3 years ago

="latex-formula">

Mathematics

1 answer:

Sonbull [250]3 years ago

8 0

It might be 8 or -8 but I am positive that it’s 8 because if u put it in the calculator it says the answer is 8

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F(x + 1) = 2x + 1<br> g(x + 1) = x-5<br> > (fog)(2) = ?

My name is Ann [436]

Can you provide me with a picture so that I can help you answer this question?

8 0

3 years ago

Find the slope of the line.

Morgarella [4.7K]

The slope:

$m=\dfrac{\Delta y}{\Delta x}$

Look at the picture.

6 units down → -6

2 units right → 2

$m=\dfrac{-6}{2}=-3$

<h3>Answer: Slope = m = -3</h3>

8 0

3 years ago

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You have 800 ft of fencing to make a pen for hogs. if you have a river on one side of your property, what is the dimension of th

schepotkina [342]

800 ÷ 3 = 266.7

Biggest possible area = 266.6 x 266.7 = 71102.00 ft²

Answer: The dimension is 266.6 ft by 266.7 ft

4 0

4 years ago

3. The three salespeople for a local advertising firm are Lola, Ahmed, and Tommy. Lola sold $2030 in ads, Ahmed sold $1540, and

dalvyx [7]

A.) First, you find the total sales. $2030 + $1540 + $1800 = $5370. Then, divide each with the total. The answer would be:

Lola: 203/537
Ahmed: 154/537
Tommy: 60/179

b.) Divide 100 by 3 for equal shares. Each person receives $33.3.

6 0

3 years ago

Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find

Papessa [141]

Answer:

1) $\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) $\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) $\text{P(at least two girls)}=\frac{1}{2}$

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To Find : The probability of each event.

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

1) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, BGG, GBB, GBG, GGB=6

$\text{P(at least one boy and one girl)}=\frac{6}{8}$

$\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, GBB=3

$\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

$\text{P(at least two girls)}=\frac{4}{8}$

$\text{P(at least two girls)}=\frac{1}{2}$

4 0

4 years ago

Read 2 more answers