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Paul [167]
4 years ago
5

Can Someone pls help me

Mathematics
2 answers:
iogann1982 [59]4 years ago
7 0

Answer:

umm 1 ot of 4

Step-by-step explanation:

Vsevolod [243]4 years ago
7 0

There are only four cards. Out of the four cards only one is nine. This means that 9 makes up \frac{1}{4} of the cards. Converting that into % is %25

Hope this helped! Let me know if I need to clarify anything!

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Mrs. stone is three times older than her younger daughter, Joyce, but only two times older than her older daughter, Alex. how ol
yarga [219]

Answer:

54

Step-by-step explanation:

RSM homework lol

made equation, then solved it.

hope this helps!

6 0
3 years ago
Which expression is equivalent to 6x³+y²-5x³+2y²​
gladu [14]

Answer:

Step-by-step explanation:

6x³ and (-5x³) are like terms

y² and 2y² are like terms

Combine like terms

6x³ + y ² - 5x³ + 2y² = 6x³ - 5x³ + y² + 2y²

                                 = x³ + 3y²

5 0
3 years ago
Ignore the problem above #3
Otrada [13]

∠a:


m∠a + 50 = 180 (because they are supplementary angles)


m∠a + 50 (-50) = 180 (-50)


m∠a = 180 - 50


m∠a = 130°


-------------------------------------------------------------------------------------------------------------------


m∠d + 65 + 50 = 180


m∠d + 115 = 180


m∠d + 115 (-115) = 180 (-115)


m∠d = 65°


-------------------------------------------------------------------------------------------------------------------


hope this helps

4 0
3 years ago
4/5 divided by 1/3 times 2/3 -2/5
Dmitry [639]

Answer:

The answer is 6/5

Step-by-step explanation:

8 0
3 years ago
Use sigma notation to represent the sum of a geometric series with a first term of 3 and a common ratio of . A. B. C. D.
maksim [4K]

Answer:

\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]

Step-by-step explanation:

A geometric sequence is a list of numbers having a common ratio. Each term after the first is gotten by multiplying the previous one by the common ratio.

The first term is denoted by a and the common ratio is denoted by r.

A geometric sequence has the form:

a, ar, ar², ar³, . . .

The nth term of a geometric sequence is ar^{n-1}

Therefore the sum of the first n terms is:

\Sigma_{k=1}^{n}(ar^{k-1})

Given a geometric series with a first term of 3 and a common ratio of 10/9, the sum of the first n terms is:

\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]

5 0
3 years ago
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