Answer:
C x=6
Step-by-step explanation:
sqrt(x+3) = x-3
Square each side
(sqrt(x+3))^2 = (x-3)^2
x+3 = (x-3)^2
x+3 = (x-3)(x-3)
FOIL
x+3 = x^2 -3x-3x+9
Combine like terms
x+3 = x^2 -6x+9
Subtract x from each side
x-x+3 = x^2 -6x-x +9
3 = x^2 -7x +9
Subtract 3 from each side
3-3 = x^2 -7x +9-3
0 = x^2 -7x+6
Factor
0 = (x-6)(x-1)
Using the zero product property
x-6=0 x-1 =0
x=6 x=1
Since we squared we need to check for extraneous solutions
x=1
sqrt(1+3) = 1-3
sqrt(4) = -2
2=-2
False
Extraneous
x=6
sqrt(6+3) = 6-3
sqrt(9) = 3
3=3
True solutions
Answer:
The answer is 7.4
Step-by-step explanation: I don’t really know a better way to tell you the explanation than just tell you the answer
Answer:
28 caffinated teas
Step-by-step explanation:
<span> Yes, there is a "relationship" regarding the </span>tangent<span> of the two acute angles (A and B) in a right triangle.</span>
