Interquartile range of the old set = 76 - 72 = 4
Interquartile range of the new set = 76 - 73 = 3
IQR of new est < old set.
The value of QR is 11
<h3>How to determine the length of QR?</h3>
The given parameters are:
RS = 5
QS = 16
Because R is on QS, then we have:
QS = QR + RS
This gives
16 = 5 + QR
Evaluate
QR = 11
Hence, the value of QR is 11
Read more about lengths at:
brainly.com/question/17297081
#SPJ1
Answer:
BE = 49
Step-by-step explanation:
In triangle BDC
65^2=56^2+BD^2
65^2-56^2=BD^2
4225-3136=BD^2
1089=BD^2
33=BD
In triangle FDE
65^2=63^2+DE^2
4225-3969=DE^2
256 = DE^2
16=DE
since ED+DB=BE
THEREFORE
16+33=BE
49=BE
Step-by-step explanation:
by the equation u put down as
F=9/5C+32
since mexico is 81°f
81=9/5C+32
81-32=9/5C
49=9/5C
49*5=9C
245=9C
C=245/9
C=27.2°
to the nearest whole number
C=27°C
Answer:
9
Step-by-step explanation:
