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3 years ago

1 and 2 are complementary angles. The measure of 1 is 54 . The measure of 2 is 6(x +1). Find the value of x.

Mathematics

1 answer:

Ede4ka [16]3 years ago

6 0

Answer:

x = 5

Step-by-step explanation:

Complementary angles are two angles that add up to 90 degrees. 90 - 54= 36, so 6(x+1), or 6x+6 = 36. You subtract 6 from both sides to get 6x=30, then divide by 6 on both sides to get x=5. So the answer would be x=5.

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Simplify (8j3 + 5j2 – 3) – (5j3 + 7j2 – 12j + 7) ...?

Free_Kalibri [48]

The answer to the problem is:

<span>8j^3 + 5j^2 - 3 - 5j^3 - 7j^2 + 12j - 7
</span>
<span>3j^3 - 2j^2 + 12j - 10
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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3 years ago

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Find the solutions to x² = 12.

Novosadov [1.4K]

Answer:

$x = \pm 2\sqrt3$

Step-by-step explanation:

Hello!

Let's use the square root property to solve this question

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3 years ago

A polynomial has a leading coefficient of 1 and the

Hoochie [10]

Answer:

(A) $[x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}]$

Step-by-step explanation:

A polynomial has a leading coefficient of 1 and the following factors with multiplicity 1:

$x-(2+i)\\x-\sqrt{2}$

We apply the following to find the factored form of the polynomial.

If a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial.

If the polynomial has an irrational root $a+\sqrt{b}$ , where a and b are rational and b is not a perfect square, then it has also a conjugate root $a-\sqrt{b}$ .

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Therefore, the factored form of the polynomial is:

$[x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}]$

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3 years ago

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Find all the solutions of sin x + cos x = 1 in the interval [0, 2pie).

Mashcka [7]

Answer:

X = 0, π/2 in the interval [0, 2pi).

Step-by-step explanation:

Use the auxiliary angle method:

R sin(x + a) = Rsin x cos a + Rcos x sin a = 1

sin x + cos x = 1

Comparing coefficients:

R cos a = 1 and R sin a = 1, so

tan a = R sin a / R cos a = 1

So a = π/4 radians.

Also R^2(sin^2 a + cos^2 a) = 1^2 + 1^2 = 2

Therefore R = √2.

So √2 sin (x +π/4 = 1

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x + π/4 = π/4

x = 0 radians

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8 0

3 years ago