All categories

2 years ago

1 and 2 are complementary angles. The measure of 1 is 54 . The measure of 2 is 6(x +1). Find the value of x.

Mathematics

1 answer:

Ede4ka [16]2 years ago

6 0

Answer:

x = 5

Step-by-step explanation:

Complementary angles are two angles that add up to 90 degrees. 90 - 54= 36, so 6(x+1), or 6x+6 = 36. You subtract 6 from both sides to get 6x=30, then divide by 6 on both sides to get x=5. So the answer would be x=5.

You might be interested in

Which is the equation of a line that passes through the point (3.-4

gtnhenbr [62]

Answer:B

Step-by-step explanation:

A. y = 2x-11

B. y = 2x-10

c. y = 2x-4

D. y=2x-2

Recall, the slope intercept equation

y= mx+c

Assuming c is held constant in each scenario

Looking at A

m = 2, c = -11

Equation of the line that passes through the point (3.-4)

-4 = 2×3 + c

c =-10

-10 does not correspond to -11 given

Let's try B

m= 2, c = -10

Equation of the line that passes through the point (3.-4)

-4 = 2×3 + c

c = -4-6 = -10

This intercept correspond with the intercept in B which is -10

Let's look at C

m= 2, c = -4

Equation of the line that passes through the point (3.-4)

-4 = 2×3 + c

c = -4-6 = -10

-10 does not correspond to -4 given

Let's try D

m= 2, c = -2

Equation of the line that passes through the point (3.-4)

-4 = 2×3 + c

c = -4-6 = -10

-10 does not correspond to -2 given

7 0

2 years ago

(x-5y,-3):(1,3y-x) find value of x and y<br>Please help me to solve thiss!!

11Alexandr11 [23.1K]

Answer:

x=11, y=2

Step-by-step explanation:

We can set 1 equal to x-5y and then solve for x. and y.

x = 5y+1

y = x-1/5

We can use this information and plug back in the values for 3y-x or x-5y.

We can set -3 = 3y-x or 1 = x-5y.

To solve for x using -3 = 3y-x we can swap the values of x and y which would make it -3 = 3(x-1/5)-5(x-1/5)+1.

We can do a bit of algebra which would get us x = 11.

Knowing that y = x-1/5 we can plug in 11 for x. y = 11-1/5.

y=2

x=11, y=2

3 0

1 year ago

In an experiment, there are n independent trials. For each trial, there are three outcomes, A, B, and C. For each trial, the pro

Mekhanik [1.2K]

Answer:

(B) No. A binomial probability model applies to only two outcomes per trial.

Step-by-step explanation:

The binomial probability is the probability of having $x$ sucesses on $n$ repeated trials of an experiment that can only have two outcomes. This is why it is called the binomial probability.

Since in our problem there are three possible outcomes, the binomial probability cannot be used.

The correct answer is (B)

(B) No. A binomial probability model applies to only two outcomes per trial.

5 0

2 years ago

Kelly needs to order lunch for orders 6 people at a business meeting. Her menu choices are chicken salad for a cost of $5 per pe

mrs_skeptik [129]

Answer:

She would be able to buy

4 Chicken Salads &

2 Egg Salads

Step-by-step explanation:

4x5=20

leaving 8 dollars

2x4=8

8 0

2 years ago

Read 2 more answers

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

2 years ago