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2 years ago

You bought items at Best Buy that rang up $143.75. You have a 30% discount and have to pay 9.5% sales tax.

Mathematics

2 answers:

Lena [83]2 years ago

5 0

Answer:

Around $110

Step-by-step explanation:

30% discount means 70% is to be paid

70/100 × 143.75

100.625

9.5% means 109.5% of 100.625 to be paid

109.5/100 × 100.625

= 110.184375

Around $110

Mandarinka [93]2 years ago

3 0

Answer:

$92.33

Step-by-step explanation:

You take 143.75 and multiply by .3 to find the amount you will discount from 145.75, to get 102.025. Then multiply that by .095 to get 9.692375. Subtract that from 102.025 to get 92.33.

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Mary and Roberto go to the movies. They buy a large popcorn for $8.50, and two medium sodas for $4.25. How much did they spend a

alukav5142 [94]

Answer:

$19.15

Step-by-step explanation:

Equation 1: 8.50+4.25+4.25= 17.00 (price of the popcorn and drinks)

Equation 2: 17.00/7.89= 2.15 (how to find how much the tax is)

Solve: 17.00+2.15=19.15 (add the tax to how much the popcorn and drinks were)

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2 years ago

How to slove this question

77julia77 [94]

The answer is A 101 see pic for work

3 0

2 years ago

A car starts from an initial velocity of 10m/s and accelerates at 2.5m/s².how long will it take the car to reach a speed of 40m/

PIT_PIT [208]

A=(v-u)/t
We know a=2.5, v=40, u=10, so:
2.5=(40-10)/t
2.5t=40-10
2.5t=30
Divide both sides by 2.5
t=12 It takes 12 seconds for the car to reach 40m/s

To find out how far it went, you do:
d=v+1/2 at^2
d=10+1/2(2.5)(12)^2
d=10+1/2(2.5)(144)
d=10+(1.25)(72)
d=10+90
d=100m

Hope this helps :)

7 0

2 years ago

Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt

-Dominant- [34]

Using the t-distribution, it is found that since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is tested if it does not outlast by more than 2 hours, that is, the subtraction is not more than 2:

$H_0: \mu_B - mu_A \leq 2$

At the alternative hypothesis, it is tested if it outlasts by more than 2 hours, that is:

$H_1: \mu_B - \mu_A > 2$

The sample means are: $\mu_A = 8.65, \mu_B = 11.23$

The standard deviations for the samples are $s_A = s_B = 0.67$

Hence, the standard errors are:

$s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934$

The distribution of the difference has mean and standard deviation given by:

$\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58$

$s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 2$ is the value tested at the hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{2.58 - 2}{0.2735}$

$t = 2.12$

The critical value for a right-tailed test, as we are testing if the subtraction is greater than a value, with a 0.05 significance level and 12 + 12 - 2 = 22 df is given by $t^{\ast} = 1.71$

Since the test statistic is greater than the critical value for the right-tailed test, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

7 0

2 years ago

Can someone help me please

ki77a [65]

x = -2.375 Hopefully that helps :)

8 0

2 years ago