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3 years ago

Graph y=−4/7x+1. do this math

Mathematics

2 answers:

Luba_88 [7]3 years ago

7 0

Answer:

Graph the line using the slope and y-intercept, or two points.

Slope: −4/7

y-intercept: 1

Fofino [41]3 years ago

3 0

Answer:

Use demos or a graphing calc.

Step-by-step explanation:

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Please help me please

kobusy [5.1K]

Terrell ran 1,000 meters more than Victor. That's the answer because if you know 1 kilometer = 1,000 meters than do 3 kilometers times 1 kilometer = 3,000 meters. Than do 4,000 meters -3,000 meters to get 1,000 meters. so the answer is Terrell ran 1,000 meters more than Victor.

7 0

3 years ago

1)There are whole numbers that are not integers.

tiny-mole [99]

Answer:

1).false 2). false 3).true 4). true

Step-by-step explanation:

1).All whole numbers are integers, so s...” That's right! All whole numbers are integers, so since 0 is a whole number, 0 is also an integer.

3).. Integers include all whole numbers and their negative counter part e.g. … -4, -3, -2, -1, 0,1, 2, 3, 4,… Where a and b are both integers. is a rational number but not an integer. 4). All integers are rational number. Since we can rewrite an integer into a fractional form by diving it by 1. For example, 4=41 4 = 4 1 . But not all rational numbers are integer.

6 0

2 years ago

Read 2 more answers

A study was conducted and two types of engines, A and B, were compared. Fifty experiments were performed using engine A and 75 u

USPshnik [31]

Answer:

a) -6 mpg.

b) 2.77 mpg

c) The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

Step-by-step explanation:

To solve this question, we need to understand the central limit theorem, and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Gas mileage A: Mean 36, standard deviation 6, sample of 50:

$\mu_A = 36, s_A = \frac{6}{\sqrt{50}} = 0.8485$

Gas mileage B: Mean 42, standard deviation 8, sample of 50:

$\mu_B = 42, s_B = \frac{8}{\sqrt{50}} = 1.1314$

Distribution of the difference:

Mean:

$\mu = \mu_A - \mu_B = 36 - 42 = -6$

Standard error:

$s = \sqrt{s_A^2+s_B^2} = \sqrt{0.8485^2+1.1314^2} = 1.4142$

A. Find the point estimate.

This is the difference of means, that is, -6 mpg.

B. Find the margin of error

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = zs = 1.96*1.4142 = 2.77$

The margin of error is of 2.77 mpg

C. Construct the 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results(5 pts)

The lower end of the interval is the sample mean subtracted by M. So it is -6 - 2.77 = -8.77 mpg

The upper end of the interval is the sample mean added to M. So it is -6 + 2.77 = -3.23 mpg

The 95% confidence interval for the difference of population mean gas mileages for engines A and B and interpret the results, in mpg, is (-8.77, -3.23).

8 0

2 years ago

Find BG.<br><br><br> ………………………….

____ [38]

BG = 40. Equation: 4(3) + 8 + 20 = 40.

4 0

2 years ago

Write one digit on each side of 23 to make a four digit multiple of 72. How many different solutions does this problem have?

user100 [1]

Answer:

This problem has two possible solutions.

2232

7236

Step-by-step explanation:

To be divisible by 72, a number has:

To be divisible by both 8 and 9 at the same time.

It is divisible by 8 if it's last two digits are divisible by 4.

It is divisible by 9 it the sum of it's digits is a number divisible by 9.

a23b

3b must be divisible by 4. In the thirties, the numbers that are divisible by 4 are 32 and 36. So b = 2 or b = 6.

a232

2 + 3 + 2 = 7

The higest possible value of a is 9 and the lowest is 1.

Between 8 and 16, only 9 is divisible by 9. So a = 2.

a = 2, b = 2 is one of the solutions.

a236

2 + 3 + 6 = 11

The higest possible value of a is 9 and the lowest is 1.

Between 12 and 20, only 18 is divisible by 9. So we need a = 7

5 0

3 years ago

Graph ​y=−4/7x+1​. do this math

Graph y=−4/7x+1. do this math