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Lelechka [254]
4 years ago
9

5x−10y=20 ​2x+4y=−16 ​​ Graph the system of equations.

Mathematics
1 answer:
FinnZ [79.3K]4 years ago
5 0
How do graph in a Chrome Book?
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A playground is rectangular with a length of 78 miles. If the area of the playground is 820 square miles, what is its width? Inp
Rudiy27

Answer:

10.5, 10\frac{1}{2}, or \frac{21}{2}

Step-by-step explanation:

To solve, you can use a variable (x) to represent the width.

The equation for area is A=L×W

So the Area is 820 and the length is 78.

820= 78w

Isolate the variable to solve.

w=10.5128....

If you round, it will be 10.5

10.5 as a fraction is 10\frac{1}{2} or \frac{21}{2}

8 0
3 years ago
Solve −27=19−2x for x . First, identify the best first step in solving this equation. What choice is correct?
Nezavi [6.7K]

Answer:

By subtracting -27 by 19 to balance the sides.

Step-by-step explanation:

-27= 19-2x

-27-19= -2x

-46= -2x

7 0
4 years ago
the dosage for an adult is 5/6 of a gram of medicine. the child dosage is 1/2 of the adult dosage.how many grams of the medicine
Artemon [7]
Your answer is about 2/6 or 3/6. Hope this helps
6 0
4 years ago
Read 2 more answers
How do I Rewrite the function by completing the square x^2+8x-29
Flura [38]

Answer:

  (x +4)^2 -45

Step-by-step explanation:

The square of a binomial has the form ...

  (x +a)^2 = x^2 +2ax +a^2

That is, the constant term (a^2) is the square of half the coefficient of the linear term: (2a/2)^2 = a^2.

To "complete the square", you add 0 in the form of the desired constant added to its opposite. Here, we want the constant for the square to be (8/2)^2 = 16. So, we can add 0 = 16 -16 to the expression:

  x^2 +8x +16 -29 -16

  (x^2 +8x +16) -45 . . . . group the terms that make the square

  (x +4)^2 -45 . . . . rewritten after completing the square

5 0
3 years ago
Please please use explanation with answer
KIM [24]

Answer:

\large\boxed{\theta=-\dfrac{\pi}{4}+k\pi\ or\ \theta=k\pi}\ for\ k\in\mathbb{Z}

Step-by-step explanation:

\tan^2\theta+\tan\theta=0\\\\\tan\theta(\tan\theta+1)=0\iff\tan\theta=0\ \vee\ \tan\theta+1=0\\\\\tan\theta=0\Rightarrow \theta=k\pi\ \text{for}\ k\in\mathbb{Z}\\\\\tan\theta+1=0\qquad\text{subtract 1 from both sides}\\\\\tan\theta=-1\Rightarrow\theta=-\dfrac{\pi}{4}+k\pi\ \text{for}\ k\in\mathbb{Z}

5 0
3 years ago
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