Ask question

Ask question

All categories

2 years ago

10

What's the area of this triangle

1 answer:

Luda [366]2 years ago

8 0

Answer:

D A = (1/2) (y₂ - y₁)(x₃ - x₁)

Step-by-step explanation:

b = (y₂ - y₁)

h = (x₃ - x₁)

A = (1/2)bh

A = (1/2) (y₂ - y₁)(x₃ - x₁)

You might be interested in

A square of side x is cut out of a larger square of side y. What is the area of the remaining

KonstantinChe [14]

Answer:

The area of the remaining figure is $y^2-x^2$

Step-by-step explanation:

<u>Area of the Square Shape</u>

Given a square of side length x, the area is calculated by the formula:

$A_x=x^2$

It's given a square of side x is cut out of a larger square of side y. Please refer to the image below.

The area of the square of side length y is:

$A_y=y^2$

The shaded area of the remaining figure is the difference between both areas:

$A=A_y-A_x$

$A=y^2-x^2$

The area of the remaining figure is $\mathbf{y^2-x^2}$

3 0

3 years ago

Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha

const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

$f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}$

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

$P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35$

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

$P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17$

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95$

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

$P(X\geq a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63$

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

$P(1.83\leq X\leq a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06$

Thus, the value of <em>a</em> is 12.06.

7 0

3 years ago

Identify the graph of the equation. What is the angle of rotation for the equation?<br><br>xy=-2.5

Maurinko [17]

Answer:

It is B. hyperbola, 45 degrees.

SteIt is p-by-step explanation:

If we rotate the standard form x^2 - y^2 = 1 through 45 degrees we get xy = 1/2.

xy = -2.5 comes from x^2 - y^2 = -5 being rotated 45 degrees.

3 0

3 years ago

Read 2 more answers

Pls help with this question I give brainliest thank uuuuu!

Snezhnost [94]

Answer:

B. 88.5

Step-by-step explanation:

first we add all the numbers :

(79 +80 +92 +92 +81 +100 +88 +98 +71 + 100+91+90) over 12

= 1062 over 12

= 88.5

[why over 12? because there's 12 numbers]

8 0

3 years ago

Given: B = 7 −3 5 −1 C = 1 −1 13 −5 Solve the equation: 2X + B = C X =

zhuklara [117]

Answer:

-3/4 and 1/-2 is the correct answer.

Step-by-step explanation:

8 0

3 years ago