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vagabundo [1.1K]
3 years ago
6

What is the resulting equation when the expression for y in the second equation is substituted into the first equation?

Mathematics
1 answer:
alexira [117]3 years ago
3 0
The answer is B

Hope I helped
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What makes 5,459,176,320 unique
Lisa [10]

Answer:

There is every digit (0-9( except for 8

Step-by-step explanation:

6 0
2 years ago
Distance on graph
Mnenie [13.5K]
The graph can be divided into two shapes. A rectangle and a right triangle.

The distance that the rover will cover if it completes one circuit can be computed using the Pythagorean theorem and adding the sides of the rectangle.

Rectangle:
Width = 4 - 2 = 2 meters 
Length = 11 - 2 = 9 meters

Triangle = 16 - 2 = 14 ; 14 - 2 = 12 meters  (this is the short leg)
long leg of the triangle = length of the rectangle = 9 meters.

12² + 9² = c²
144 + 81 = c² 
225 = c² 
√225 = √c²
15 = c

Point A to B = 4 - 2 = 2 meters
Point B to C = 15 meters
Point C to D = 16 - 2 = 14 meters
Point D to A = 11 - 2 = 9 meters

Total distance traveled = 2 + 15 + 14 + 9 = 40 meters.
6 0
3 years ago
S=(1 r)<br> c. find c if s = r 174 and r= 45%
stepladder [879]
The question is incorrect because of the apparent contradiction the question makes.
First statement says that a quantity S is equal to quantity r.
The second statement says that S = 174r. 
Moreover, the quantity C is not correctly linked with the equation. Please either correct the question or explain the ambiguity.
4 0
3 years ago
Use the discriminant to determine how many real number solutions exist for the quadratic equation –4j2 + 3j – 28 = 0. A. 3 B. 2
Zepler [3.9K]

Answer:

C. 0

Step-by-step explanation:

–4j^2 + 3j – 28 = 0

The discriminant is b^2-4ac  if >0 we have 2 real solutions

                                                   =0  we have 1 real solutions

                                                   <0 we have 2 imaginary solutions

a = -4, b =3  c = -28

b^2 -4ac

(3)^2 - 4(-4)*(-28)

9 - 16(28)

9 -448

This will be negative so we have two imaginary solutions.

Therefore we have 0 real solutions

5 0
3 years ago
What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?
s344n2d4d5 [400]

Answer:

2 units

Step-by-step explanation:

The given equation of the circle is:

x^{2} + y^{2}+8x-6y+21=0

The general equation of the circle is:

x^{2} + y^{2}+2gx+2fy+c=0

Comparing the given equation with the general equation we can say:

g = 4

f = -3

c = 21

The formula for radius of the circle is:

radius=\sqrt{g^{2} +f^{2} -c }

Using these values of the given circle, we get:

radius=\sqrt{(4)^{2}+(-3)^{2}-21}\\\\radius=\sqrt{4}\\\\radius=2

Therefore, the length of radius of the given circle is 2.

3 0
3 years ago
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