Turn each number into the product of it's prime factors.
32=16x2=2x2x2x2x2=2^5
48=24*2=6x4x2=2x3x2x2x2
Pick the highest number that occurs. In this case it is 2. Now we have to see how many times it appears in both. It appears 5 times in 32 and 4 times in 48. 4 is the highest number of times it appears in the numbers so:
2^4=2x2x2x2=16
The Greatest Common Factor (GCF) of 32 and 48 is 16.
General formula for circles at the origin is x^2+y^2=R^2 where R is the radius.So R^2=4225. Solve for R.
Answer:c
Step-by-step explanation:
when you set (x-6) and (x-1) to zero you get 6 and 1
Answer:
The point at (-7, -5) = a
The point at (9, 3) = b
The point at (-3, 7) = c
The "a" point of the triangle is 12 units away from the center point.
So, 12 x 1/4
=> 12/4
=> 3
So, the "a" point of the dilated figure is 3 units left from the center.
=> So, the dilated "a" point is at (2, -5)
The "b" point is 8/4 (= rise/run = y-axis / x-axis) from the center point.
=> 8/4 = 2
So, the "b" point of the dilated figure is 1 unit right and 2 units up from the center point.
=> So, the dilated "b" point is at (6, -3)
The "c" point is 12/8 units away from the center point.
=> 12/8 x 1/4
=> 3/2
So, the "c" point of the dilated figure is 3 units up and 2 units left from the center point.
=> So, the dilated "c" point is at (3, -2)
Answer:
Option C 
Step-by-step explanation:
Let
x ------> the cost of each shirt
we know that
The cost of 5 shirts plus $10 (amount of money that would remain) must be equal to the cost of 3 shirts plus $24 (amount of money that would remain). Considering that the cost of the shirts is the same
The linear equation that represent this scenario is

Solve for x


