Length of the actual bathroom = 20 x 2 inches = 40 inches = 10/3 ft
Width of the actual bathroom = 20 x 3.5 inches = 70 inches = 35/6 ft
Area of the actual bathroom = length x width = 10/3 x 35/6 = 19 square ft.
Answer:
C
Step-by-step explanation:
the sum of complementary angles = 90°, hence
x + 5 + x - 9 = 90
2x - 4 = 90 ( add 4 to both sides )
2x = 94 ( divide both sides by 2 )
x = 47
Thus ∠DFG = 47 + 5 = 52° and ∠JKL = 47 - 9 = 38°
Area (a) as a function of radius (r) might be written
a(r) = πr²
Answer:
Hey there!
<u>What we know:</u>
- The three triangles (two smaller ones and one larger one, are all right triangles)
- Measure of angle A is 42 degrees.
- Measure of angle C is 58 degrees.
- AC is 65 m.
<u>What we would like to know:</u>
First, let's find AB.
Sine 58= AB/65
Solving for AB, we see that it is about 55.12 m.
Next, let's find BD.
Sine 42= BD/55.12
Solving for BD, we see that it is about 36.88 m.
Let me know if this helps :)
