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tia_tia [17]
3 years ago
12

Can someone show me how to solve this

Mathematics
2 answers:
NISA [10]3 years ago
7 0

Answer:

f(1)=13

f(-9)=88

f(0)=0

f(-15)=20

The above mentioned are false statements

Step-by-step explanation:

f(1)=13 : false because "13" is out of range -40≤f(x)≤-10

f(-9)=88 : false because "88" is out of range -40≤f(x)≤-10

f(0)=0 : false because "0" is out of range -40≤f(x)≤-10

f(-15)=-20 : false because "-15" is out of domain -10≤x≤20

sergij07 [2.7K]3 years ago
7 0

If the domain is -10\leq x \leq 20, it means that you can only accept inputs between -10 and 20.

In other words, you can write f(x) only is x is between -10 and 20.

This rules out the option f(-15)=-20, because you can't accept -15 as input, because it's less than -10.

Similarly, if the range is -40\leq f(x) \leq -10, it means that the function can only output numbers between -40 and -10.

In other words, you can write f(x)=k only is k is between -40 and -10.

This rules out the first two options, because their output is positive, and also f(0)=0

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Answer:

10 ft.

Step-by-step explanation:

8.8 ÷ 4= 2.2

22÷2.2= 10

6 0
3 years ago
10x + 4y = 24 6x +12y = 48 What is the value of y? * <br>A. 7 <br>B. 7/2 <br>C. 1 <br>D. -7/2​
ziro4ka [17]

Answer:

B

Step-by-step explanation:

1) lets use elimination to solve this:

multiply 10x+4y=24 with 3 in order to get "4y" into "12y"

3(10x+4y=24)

30x+12y=72

now subtract both equations to eliminate 'y"

30x+12y=72

-

6x+12y=48

---------------------

24x=24

x=1

now substitute 1 in the above equation:

6(1)+12y=48

6+12y=48

12y=42

y=7/2

4 0
3 years ago
Can somebody please help me
Ksenya-84 [330]

Answer:

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Step-by-step explanation:

8 0
3 years ago
200 to 170 what is the percentage discount offered
wel

Answer:

85%

Step-by-step explanation:

Convert fraction (ratio) 170 / 200 Answer: 85%

6 0
4 years ago
Given the list of terms 1/3​, 1, 5/3, 7/3,.... Find the 15th and −16th term.
qwelly [4]

Answer:

15th term =29/3

16th term = 31/3

Step-by-step explanation:

Given an arithmetic sequence with the first term a1 and the common difference d , the nth (or general) term is given by an=a1+(n−1)d .

First we find the 15th term

n=15

a1=1/3

d=1 - 1/3 = 2/3

Solution

1/3+(15-1)2/3

1/3+28/3

(1+28)/3

29/3

Lets find the 16th term

1/3+(16-1)2/3

1/3+30/3

(1+30)/3

31/3

8 0
3 years ago
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