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Neko [114]
3 years ago
11

PLEASE HELP IT’S DUE TMR

Mathematics
1 answer:
irakobra [83]3 years ago
4 0
The anwser to the first one is 0.6
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In the triangle below, what is the approximate value of x?
Allushta [10]

Answer:

hi

apply BPT

\frac{4}{18}  =  \frac{x}{22}

solve it now

x = 88/18 approx = 4.9 inches

3 0
2 years ago
An item is regularly priced at $40 It is on sale for 30% off the regular price. How much (in dollars) is discounted from the reg
Ipatiy [6.2K]

12 dollars is discounted off, making the price 28 dollars.

Step-by-step explanation:

10 percent is 4$, 4×3=12

5 0
2 years ago
Plz help answer fast
spayn [35]

Answer:

d because it does not looks somlar

5 0
2 years ago
Read 2 more answers
Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂=  ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for  π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

5 0
3 years ago
A rectangle has an area of x3 + x2 – 7x + 2 square meters and a width of x – 2 meters. Find its length.
horrorfan [7]
The distance beween the points is 3\sqrt{} 13
3 0
3 years ago
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