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bija089 [108]
3 years ago
15

Someone please help me on this question! It would mean a lot, this is my last day of school and I need to pass this to pass my g

rade. Please help me!

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0
You need to multiply the amount of loaves by the weight of one loaf: 
(6)(1 \frac{1}{4} )= (\frac{6}{1} )( \frac{5}{4} )= \frac{30}{4} =7 \frac{1}{2}. 
7.5 = 120 ounces.

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Write an equation for the line<br><br> With a slope of -3 and a y-intercept of 1 ________
pashok25 [27]

y=-3x+1 is the equation

3 0
3 years ago
If 4x^2 - 100 = 0, the roots of the equation are
ololo11 [35]
4x^2-100=0 \ \ \ \ \ \ |+100 \\&#10;4x^2=100 \ \ \ \ \ \ \ \ \ \ \  |\div 4 \\&#10;x^2=25 \\&#10;x=\pm \sqrt{25} \\&#10;x=\pm 5 \\&#10;x=-5 \hbox{ or } x=5

The answer is (3) -5 and 5.
5 0
3 years ago
Please help!!! I don’t understand!
soldier1979 [14.2K]

Answer:

y = 3x

Step-by-step explanation:

:)

:)

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3 0
2 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
WILL GIVE BRAINLIEST!!!
Natalka [10]
Volume of a cylinder= (height) x area of the base (circle)

We know the height = 160 cm (given), let's find the radius of the base.

The circumference of the base = 87.92 = 2πR==> R=87.92/(2π) =13.993 cm

Area of circle = πR²=π(13.993)² = 615.128 cm²

Hence the volume of the cylinder = 615.128 x 160 = 92,420.48 cm³
4 0
3 years ago
Read 2 more answers
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