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SSSSS [86.1K]
3 years ago
8

Is 5/6 greater than 24/30

Mathematics
1 answer:
Harrizon [31]3 years ago
5 0

Answer:

Yes

Step-by-step explanation:

The fraction 4/5 is equivalent to 24/30 (To get this I multiplied both the numerator and denominator by 6). The fraction 5/6 is equivalent to 25/30 (To get this I multiplied both the numerator and denominator by 5).... Since 25 is greater than 24, 25/30 (or originally 5/6) is the larger fraction

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Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60)  C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0
2 years ago
Identify this conic section. 16y = x^2
kiruha [24]

ANSWER

A parabola.

EXPLANATION

The given conic is :

16y =  {x}^{2}

This can be rewritten as:

{x}^{2}  = 16y

{x}^{2}  = 4(4)y

This is a parabola with the vertex at the origin.

The foci is (0,4)

Therefore the given conic section is a parabola that has an axis of symmetry parallel to the y-axis.

7 0
3 years ago
PLEASE HELP!!! <br> find the length of arc LN. Round to the nearest hundredth.<br> SHOW WORK....
patriot [66]

9514 1404 393

Answer:

  15.71 units

Step-by-step explanation:

The arc length is given by the formula ...

  s = rθ

where r represents the radius, and θ represents the central angle in radians.

The angle of 60° is π/3 radians, so the arc length is ...

  s = 15(π/3) = 5π ≈ 15.71 . . . units

  LN ≈ 15.71 units

__

<em>Note</em>: if you use 3.14 for π, you will get 15.70.

6 0
2 years ago
-7–5(3g+8)&lt;10g–7+g <br><br> help me please!
Ede4ka [16]

Answer:

-20/13 <g

Step-by-step explanation:

-7–5(3g+8)<10g–7+g

Distribute

-7–15g-40<10g–7+g

Combine like terms

-15g - 47 < 11g -7

Add 15 g to each side

-15g+15g -47< 11g+15g -7

-47 < 26g -7

Add 7 to each side

-47+7 < 26g-7+7

-40 < 26g

Divide each side by 26

-40/26 <26g/26

-40/26 <g

Divide top and bottom by 2

-20/13 <g

8 0
3 years ago
4 + 3s + 2<br> Terms:<br> Coefficients:<br> Constants:<br> Answer
USPshnik [31]

▬▬▬▬▬▬▬▬▬▬▬▬

<h3>4 + 3s + 2 </h3>

→ Terms - <u>Three</u> (<u>Trinomial</u>)

→ Coefficient - <u>3</u>

→ Constants - <u>4</u> and <u>2</u>

▬▬▬▬▬▬▬▬▬▬▬▬

8 0
2 years ago
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