see the attached figure with the letters
1) find m(x) in the interval A,BA (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100
2) find m(x) in the interval B,CB(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20
3)
find n(x) in the interval A,BA (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x
4) find n(x) in the interval B,CB(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30
5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44
6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72
for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72
<span> h'(x) = 1.44 ------------ > not exist</span>
ANSWER
A parabola.
EXPLANATION
The given conic is :

This can be rewritten as:


This is a parabola with the vertex at the origin.
The foci is (0,4)
Therefore the given conic section is a parabola that has an axis of symmetry parallel to the y-axis.
9514 1404 393
Answer:
15.71 units
Step-by-step explanation:
The arc length is given by the formula ...
s = rθ
where r represents the radius, and θ represents the central angle in radians.
The angle of 60° is π/3 radians, so the arc length is ...
s = 15(π/3) = 5π ≈ 15.71 . . . units
LN ≈ 15.71 units
__
<em>Note</em>: if you use 3.14 for π, you will get 15.70.
Answer:
-20/13 <g
Step-by-step explanation:
-7–5(3g+8)<10g–7+g
Distribute
-7–15g-40<10g–7+g
Combine like terms
-15g - 47 < 11g -7
Add 15 g to each side
-15g+15g -47< 11g+15g -7
-47 < 26g -7
Add 7 to each side
-47+7 < 26g-7+7
-40 < 26g
Divide each side by 26
-40/26 <26g/26
-40/26 <g
Divide top and bottom by 2
-20/13 <g
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<h3>4 + 3s + 2 </h3>
→ Terms - <u>Three</u> (<u>Trinomial</u>)
→ Coefficient - <u>3</u>
→ Constants - <u>4</u> and <u>2</u>
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