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olga nikolaevna [1]
3 years ago
14

Which system of linear equations has the ordered pair (-2,8) as its solution?

Mathematics
1 answer:
Nana76 [90]3 years ago
6 0

Answer:

The solution to the system of linear equations is:

(x, y) = (-2, 8)

Hence, y - 2x = 12 and x - 2y = -18  has the ordered pair (-2,8) as its solution. Thus, option A is correct.

Step-by-step explanation:

Checking the first system of equations

y - 2x = 12

x - 2y = -18

solving the first system of equations

\begin{bmatrix}y-2x=12\\ x-2y=-18\end{bmatrix}

\mathrm{Multiply\:}y-2x=12\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:2y-4x=24

\begin{bmatrix}2y-4x=24\\ -2y+x=-18\end{bmatrix}

adding the equations

-2y+x=-18

+

\underline{2y-4x=24}

-3x=6

\begin{bmatrix}2y-4x=24\\ -3x=6\end{bmatrix}

solving -3x=6 for x

-3x=6

Divide both sides by -3

\frac{-3x}{-3}=\frac{6}{-3}

Simplify

x=-2

\mathrm{For\:}2y-4x=24\mathrm{\:plug\:in\:}x=-2

2y-4\left(-2\right)=24

2y+8=24

Subtract 8 from both sides

2y+8-8=24-8

Simplify

2y=16

Divide both sides by 2

\frac{2y}{2}=\frac{16}{2}

Simplify

y=8

Therefore, the solution to the system of linear equations is:

(x, y) = (-2, 8)

Hence, y - 2x = 12 and x - 2y = -18  has the ordered pair (-2,8) as its solution. Thus, option A is correct.

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