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slega [8]
3 years ago
13

Plzz do correctly worth a lot of points

Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0

Answer:

-9 Would be the answer I would believe.

Step-by-step explanation:

-9 Would be the answer I would believe.

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Write words to match the expression.<br><br> 3+(4*12)
denpristay [2]

3 more than the product of 4 and 12.

5 0
3 years ago
Which expression is equivalent to<br> on is equivalent to 9x^5y^16/45x^5y^4?
kicyunya [14]

Answer:

\frac{y^{12} }{5}

Step-by-step explanation:

Check the attached photo for the details

6 0
3 years ago
3x^2 Type of expression coefficients and constant
Contact [7]

Answer & Step-by-step explanation:

3x²

This term represents a monomial expression. Mono- means one. This term is by itself. It has no other term added or subtracted to it.

The coefficient of this term is 3 because it is the number that the variable is connected to.

There are no constants because this is a monomial expression.

5 0
2 years ago
What is the area of the shaded region below?<br> 7 m<br> 30 m<br> 7 m<br> 21 m
Rama09 [41]

Answer:

322.28

A

Step-by-step explanation:

Area of the rectangle

L = 30

W = 21

Area = 30 * 21

Area = 630

Area of the circles

Radius = 7 m

Area = pi r^2

Area = 3.14 * 7^2

Area = 153.86 m^2

Area of both circles = 307.72

Area of the Shaded Region

Area of shaded region = area of the rectangle - area of 2 circles.

Area of Shaded Region = 630 - 307.72

Area of Shaded Region = 322.28

5 0
2 years ago
. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

  • Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
  • Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
2 years ago
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