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Art [367]
3 years ago
11

Please help me with this problem

Mathematics
1 answer:
Andreyy893 years ago
8 0

Answer:

it's 10

Step-by-step explanation:

10,000 /  1,000 = 10 right so than it says it less than a 100 but more than a 1 so it,s 10

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Please help<br> Thank you!!!!
Anni [7]

Answer:

The unknown angle would be 107 degrees.

6 0
3 years ago
Read 2 more answers
Rapid Rental Car Company charges a $55 rental fee and $0.25 per mile driven. For the same car, Capital Cars charges $45 for rent
AlladinOne [14]

Answer:

100 miles

Step-by-step explanation:

Let the number of miles driven = x

Rapid Rental Car Company charges a $55 rental fee and $0.25 per mile driven.

$55 + $0.25x

55 + 0.25x

For the same car, Capital Cars charges $45 for rental fee and $0.35 per mile.

$45 + $0.35x

45 + 0.35x

Equation :

55 + 0.25x = 45 + 0.35x

The number of miles for which the companies’ charges will be the same is calculated as:

55 + 0.25x = 45 + 0.35x

Collect like terms

55 - 45 = 0.35x - 0.25x

10 = 0.10x

x = 10/0.10

x = 100 miles

The number of miles for which the companies’ charges will be the same is

100 miles.

3 0
3 years ago
If the first term of a geometric sequence is positive, and r&gt;1, then the sequnce increases?
Dvinal [7]

Answer:

Yes, if the first term of a geometric sequence is positive and r > 1, then the sequence increases

Step-by-step explanation:

* Lets talk about the geometric sequence

- There is a constant ratio between each two consecutive numbers

- Ex:

# 5  ,  10  ,  20  ,  40  ,  80  ,  ………………………. (×2)

# 5000  ,  1000  ,  200  ,  40  ,  …………………………(÷5)

* General term (nth term) of a Geometric sequence:

# U1 = a  ,  U2  = ar  ,  U3  = ar2  ,  U4 = ar3  ,  U5 = ar4

# Un = ar^n-1, where a is the first term , r is the constant ratio

  between each two consecutive terms, and n is the position of

 the number in the sequence

- V.I.N: The position of the number means the place of the

 number like first , second , third , .......... so n must be positive integer

* Lets talk about the ratio r

- If r greater than 1 and a is positive, the sequence increases lets

 take some different examples to explain that

# If the first term is 2 and the ratio between the consecutive

  terms is 3/2, then the first four terms in the sequence are

∵ a = 2

∵ r = 3/2 ⇒ greater than 1

∴ First = a = 2

∴ Second = ar = 2 × 3/2 = 3

∴ Third = ar² = 2 × (3/2)² = 2 × 9/4 = 9/2 4.5

∴ Fourth = ar³ = 2 × (3/2)³ = 2 × 27/8 = 27/4 = 6.75

- From the answers the sequence increases

# If the first term is 1/2 and the ratio between the consecutive

  terms is 4/3, then the first four terms in the sequence are

∵ a = 1/2

∵ r = 4/3 ⇒ greater than 1

∴ First = a = 1/2

∴ Second = ar = 1/2 × 4/3 = 2/3 ⇒ 2nd > 1st

∴ Third = ar² = 1/2 × (4/3)² = 2 × 16/9 = 8/9 ⇒ 3rd > 2nd

∴ Fourth = ar³ = 1/2 × (4/3)³ = 2 × 64/27 = 32/27 ⇒ 4th > 3rd

- From the answers the sequence increases

* Now we are sure if the first term of a geometric sequence is

 positive and r > 1, then the sequence increases

3 0
3 years ago
Read 2 more answers
What kind of function would be most suitable to model these data
Darya [45]

Answer:

an exponential

Step-by-step explanation:

just did on edg.

8 0
4 years ago
Find a factorization of x² + 2x³ + 7x² - 6x + 44, given that<br> −2+i√√7 and 1 - i√/3 are roots.
Levart [38]

A factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

<h3>What are the properties of roots of a polynomial?</h3>
  • The maximum number of roots of a polynomial of degree n is n.
  • For a polynomial with real coefficients, the roots can be real or complex.
  • The complex roots of a polynomial with real coefficients always exist in a pair of conjugate numbers i.e., if a+ib is a root, then a-ib is also a root.

If the roots of the polynomial p(x)=ax^4+bx^3+cx^2+dx+e are r_1,r_2,r_3,r_4, then it can be factorized as p(x)=(x-r_1)(x-r_2)(x-r_3)(x-r_4).

Here, we are to find a factorization of p(x)=x^4+2x^3+7x^2-6x+44. Also, given that -2+i\sqrt{7} and 1-i\sqrt{3} are roots of the polynomial.

Since p(x)=x^4+2x^3+7x^2-6x+44 is a polynomial with real coefficients, so each complex root exists in a pair of conjugates.

Hence, -2-i\sqrt{7} and 1+i\sqrt{3} are also roots of the given polynomial.

Thus, all the four roots of the polynomial p(x)=x^4+2x^3+7x^2-6x+44, are: r_1=-2+i\sqrt{7}, r_2=-2-i\sqrt{7}, r_3=1-i\sqrt{3}, r_4=1+i\sqrt{3}.

So, the polynomial p(x)=x^4+2x^3+7x^2-6x+44 can be factorized as follows:

\{x-(-2+i\sqrt{7})\}\{x-(-2-i\sqrt{7})\}\{x-(1-i\sqrt{3})\}\{x-(1+i\sqrt{3})\}\\=(x+2-i\sqrt{7})(x+2+i\sqrt{7})(x-1+i\sqrt{3})(x-1-i\sqrt{3})\\=\{(x+2)^2+7\}\{(x-1)^2+3\}\hspace{1cm} [\because (a+b)(a-b)=a^2-b^2]\\=(x^2+4x+4+7)(x^2-2x+1+3)\\=(x^2+4x+11)(x^2-2x+4)

Therefore, a factorization of x^4+2x^3+7x^2-6x+44 is (x^2+4x+11)(x^2-2x+4).

To know more about factorization, refer: brainly.com/question/25829061

#SPJ9

3 0
1 year ago
Read 2 more answers
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