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Wewaii [24]
3 years ago
11

Jerry plays tennis once every 6 days. Sam plays tennis every 10 days and Leo comes once every 12 days. This Monday all of them p

layed. How many days after this Monday will all of them meet at the tennis court again?
Mathematics
1 answer:
Stells [14]3 years ago
5 0

Answer:

They'll meet at the court again in 60 days after this monday.

Step-by-step explanation:

In order to calculate the number of days from monday that it will take for them to meet again, we need to calculate the LMC of the frequency at which they go to the court. To do that we must take the numbers and divide the 3 of them until they're all equal to 1, then we multiply all the numbers that were used to divide them.

12 | 10 | 6    / 2

6 | 5 | 3      /2

3 | 5 | 3      /3

1 | 5 | 1       /5

1 | 1 | 1

The LMC is equalt o 2*2*3*5 which is 60.

They'll meet at the court again in 60 days after this monday.

       

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A quiz consists of 10 true or false questions. To pass the quiz a student must answer at least eight questions correctly.
lys-0071 [83]

Answer:

The probability of  the student will pass the quiz = .0546

Step-by-step explanation:

Given -

Total no of question = 10

If the student guesses on each question there are two outcomes true of false

the probability  of guesses  question correctly =  \frac{1}{2}

the probability  of success is (p) =  \frac{1}{2}

the probability  of guesses  question incorrectly = \frac{1}{2}

the probability  of failure is (q) = 1- p = \frac{1}{2}

If the student guesses on each question he must answered at least 8 question correctly

the probability of  the student will pass the quiz = P(X\geq8 )

= P(X = 8 ) + P(X = 9) + P(X = 10 )

= \binom{10}{8}(p)^{8}(q)^{10 - 8} + \binom{10}{9}(p)^{9}(q)^{10 - 9} + \binom{10}{10}(p)^{10}(q)^{10 - 10}

= \frac{10!}{(2!)(8!)}(\frac{1}{2})^{8}(\frac{1}{2})^{10 - 8} +\frac{10!}{(1!)(9!)} (\frac{1}{2})^{9}(\frac{1}{2})^{10 - 9} + \frac{10!}{(0!)(10!)}(\frac{1}{2})^{10}(\frac{1}{2})^{10 - 10}

= 45\times\frac{1}{2^{10}} + 10\times\frac{1}{2^{10}} + 1\times\frac{1}{2^{10}}

= \frac{56}{2^{10}}

= .0546

5 0
3 years ago
Sonya can walk 6 kilometers in 3 hours. If she has to walk 10 kilometers, how much time will it take her?
vekshin1
1.8 hours because 6 km is to 3 hours as 10 km is to x hours. So you multiply 3*6 and them divide it by 10
4 0
3 years ago
The two quadrilaterals below are similar. What is the length of EF?
damaskus [11]

EF = 15 cm.

Step-by-step explanation:

Step 1:

If the quadrilaterals, ABCD and EFGH are similar their side lengths will be of the same ratio throughout.

Comparing the quadrilaterals, we have AB and EF are similar, BC and FG are similar, CD and GH are similar, DA and HE are similar.

So the ratio of all these sides will be equal.

Step 2:

\frac{AB}{EF} :\frac{BC}{FG} : \frac{CD}{GH} :\frac{DA}{HE} .

Of these lengths, we only have the values for AB, BC, CD, DA, GH, HE and need to determine the length of EF. By substituting the known values the ratio becomes;

\frac{5}{EF} :\frac{4}{12} :\frac{6}{18} .

\frac{5}{EF} : \frac{1}{3} : \frac{1}{3} .

So EF = 3(5) = 15 cm. Which is the second option.

6 0
3 years ago
Solve the compound inequality for x and identify the graph of its solution.
RoseWind [281]

Step-by-step explanation:

Given, 3x−2<2x+1

⇒3x−2x<1+2

⇒x<3orx∈(−∞,3)

The lines y=3x−2 and y=2x+1 both will intersect at x=3

Clearly, the dark line shows the solution of 3x−2<2x+1.

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Katen [24]

52.94% of the viewers prefer videos on a mobile or laptop device

<h3>How to determine the percentage?</h3>

The given parameters are

Viewers that prefer videos on a mobile or laptop device = 18

Total number of viewers = 34

The percentage of voters in this category is then calculated as

Percentage = 18/34 * 100%

Evaluate the expression

Percentage = 52.94%

Hence, 52.94% of the viewers prefer videos on a mobile or laptop device

Read more about percentages at:

brainly.com/question/843074

#SPJ1

3 0
2 years ago
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