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Thepotemich [5.8K]
3 years ago
8

The image type used for graphics that need smaller sizes with no loss of quality is a ___________.

Computers and Technology
1 answer:
Novosadov [1.4K]3 years ago
4 0
I believe the answer it TIF 
You might be interested in
Isabella's manager has asked her to write up a _____ that describes their company's interest in developing a custom software sol
kakasveta [241]

Answer:

Request for information (RFI)

Explanation:

Request for Information is a business process document that contains information about an organization's capability to deliver solutions to a potential client. The RFI document will contain information that will help for decision making by clients. Other similar business documents in this line are Request for tender (RFT), request for quotation (RFQ).

6 0
3 years ago
What two actions does the RETI instruction perf orm? Why must these two actions be done in a single instruction, as opposed to a
Bas_tet [7]

Answer:

In assembly language, two instructions control the use of the assembly language procedure.

  • CALL
  • RET

CALL pushed the control to the return address onto the stack and transferred the control.

RET instruction returns the address that placed on the stack by a call instruction.

Explanation:

Action RET instruction

  • The RET instruction pops the address and returns off the stack, which is pointed by the stack pointer.
  • The stack is LIFO in memory at a particular location, and the pointer points offset from the stack location.

RET instruction does its job by consulting the register and memory state at the point when it is executed.

In RET instruction, only register and memory state is executed. Call instruction must save that address that figure out in a register and memory location.

5 0
3 years ago
This program will store roster and rating information for a soccer team. Coaches rate players during tryouts to ensure a balance
aksik [14]

Answer:

import java.util.Scanner;

public class TeamRoster {

  public static void main(String[] args) {

     Scanner scan = new Scanner(System.in);

     int[][] players = new int[5][2];

     boolean keepAlive = true;

     char input;

     

     for (int i = 0; i < 5; i++) {

        System.out.println("Enter player " + (i+1) + "'s jersey number: ");

        players[i][0] = scan.nextInt();

        if( players[i][0] >= 0 && players[i][0] < 100 ) {

             System.out.println("Enter player number less than 100");

               System.out.println("Enter player " + (i+1) + "'s rating: ");

               players[i][1] = scan.nextInt();

               if ( players[i][1] >= 1 && players[i][1] <10 ) {

                     System.out.println();

               }    else {

                     System.out.println("Enter player " + (i+1) + "'s rating: ");

                     players[i][1] = scan.nextInt();

               }

     }

     }

     System.out.println();

     outputRoster(players, 0);

     

     while (keepAlive) {

        outputMenu();

        input = scan.next().charAt(0);

        if (input == 'q') {

           keepAlive = false;

           break;

        } else if (input == 'o') {

           outputRoster(players, 0);

        } else if (input == 'u') {

           System.out.println("Enter a jersey number: ");

           int jerseyNum = scan.nextInt();

           System.out.println("Enter a new rating for the player: ");

           int newRating = scan.nextInt();

           for (int l = 0; l < 5; l++) {

              if (players[l][0] == jerseyNum) {

                 players[l][1] = newRating;

              }

           }

        } else if (input == 'a') {

           System.out.println("Enter a rating: ");

           int rating = scan.nextInt();

           outputRoster(players, rating);

        } else if (input == 'r') {

           System.out.println("Enter a jersey number: ");

           int jerseyNum = scan.nextInt();

           boolean exists = true;

           for (int l = 0; l < 5; l++) {

              if (players[l][0] == jerseyNum) {

                 System.out.println("Enter a new jersey number: ");

                 players[l][0] = scan.nextInt();

                 System.out.println("Enter a rating for the new player: ");

                 players[l][1] = scan.nextInt();

              }

           }

           

        }

     }

     

     return;

  }

   

  public static void outputRoster(int[][] players, int min) {

     System.out.println(((min>0) ? ("ABOVE " + min) : ("ROSTER")));

     int item = 1;

     for (int[] player : players) {

        if (player[1] > min) {

           System.out.println("Player " + item + " -- Jersey number: " + player[0] + ", Rating: " + player[1]);

        }

        item++;

     }

     System.out.println();

  }

   

  public static void outputMenu() {

     System.out.println("MENU");

     System.out.println("u - Update player rating");

     System.out.println("a - Output players above a rating");

     System.out.println("r - Replace player");

     System.out.println("o - Output roster");

     System.out.println("q - Quit\n");

     System.out.println("Choose an option: ");  

  }

}

Explanation:

The program is written in Java.

It is a bit straightforward.

The Scanner module is declared and used to collect input from the user.

The program prompts the user for each player jersey then rating.

All five players details are collected.

The program shows the output of all the entries.

5 0
3 years ago
Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth
telo118 [61]
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}


So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.


4 0
3 years ago
An intruder with malicious intent breaks into an office and steals a hard drive
kakasveta [241]

Answer: data security

Explanation:

The company's authentication protocols and data encryption measures denotes data security.

Data security simply means protecting unauthorized people from having access to a particular data. This is done to prevent unauthorized access of important information or to prevent fraud. Some of the data security measures include data encryption, tokenization, hashing, etc.

4 0
3 years ago
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