1,2,3 need help please show work
2 answers:
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Detailed explanation below
Answer:
dA/dt= 12-2A(t)/900+t
Step by step Explanation:
Given:
rate of 3 gal/min
concentration of the solution entering is 4 lb/gal,
The equation of the solution can be expressed as
dA/dt = R(1)- R(2)
Where R(1)=( concentration of the salt at inflow* rate of input of given brine)
R(2)= ( concentration of the salt at inflow* rate of output of given brine)
R(1)= 3 gal/min× 4 lb/gal=12Ib/min
But the solution is been pumped slowly, the rate of the accumulation can calculated as;
(3 gal/min- 2 gal/min)=1gal/min
But after t min we will be having 900+t gallons present in the tank
CHECK THE ATTACHMENT FOR COMPLETE EXPLANATION
